Reputation: 2367
I have a string of data like FF0000FF
and I want to write that to a file as raw 8-bit bytes 11111111 00000000 00000000 11111111
. However, I seem to end up getting way to much data FF
turns into FF 00 00 00
when using struct.pack
or I get a literal ASCII version of the 0's and 1's.
How can I simply take a string of hex and write that as binary, so when viewed in a hex-editor, you see the same hex string?
Upvotes: 14
Views: 25077
Reputation: 405
You could use bytes
's hex
and fromhex
like this:
>>> ss = '7e7e303035f8350d013d0a'
>>> bytes.fromhex(ss)
b'~~005\xf85\r\x01=\n'
>>> bb = bytes.fromhex(ss)
>>> bytes.hex(bb)
'7e7e303035f8350d013d0a'
Upvotes: 3
Reputation: 968
In Python 3.x you can just use the b prefix in front of modified form of the string, and then write it out to a binary file like so:
hex_as_bytes = b"\xFF\x00\x00\xFF"
with open("myFileName", "wb") as f: f.write(hex_as_bytes)
Upvotes: 0
Reputation: 24021
You're looking for binascii.
binascii.unhexlify(hexstr)
Return the binary data represented by the hexadecimal string hexstr.
This function is the inverse of b2a_hex(). hexstr must contain
an even number of hexadecimal digits (which can be upper or lower
case), otherwise a TypeError is raised.
import binascii
hexstr = 'FF0000FF'
binstr = binascii.unhexlify(hexstr)
Upvotes: 19