Reputation: 21
If Im trying to check an input 5 byte array (p) against a 5 byte array stored in flash (data), using the following function (e2CheckPINoverride), to simply return either a true or false value. But it seems, no matter what I try, it only returns as 'false'.
I call the function here:
if (e2CheckPINoverride(pinEntry) == 1){
PTDD_PTDD1 = 1;
}
else{
PTDD_PTDD1 = 0;
}
Here is the function:
BYTE e2CheckPINoverride(BYTE *p)
{
BYTE i;
BYTE data[5];
if(e2Read(E2_ENABLECODE, data, 5)) {
if(data[0] != p[0]) return FALSE;
if(data[1] != p[1]) return FALSE;
if(data[2] != p[2]) return FALSE;
if(data[3] != p[3]) return FALSE;
if(data[4] != p[4]) return FALSE;
}
return TRUE;
}
I have already assigned true and false in the defines.h file:
#ifndef TRUE
#define TRUE ((UCHAR)1)
#endif
#ifndef FALSE
#define FALSE ((UCHAR)0)
#endif
and where
typedef unsigned char UCHAR;
when i step through the code, it performs all the checks correctly, it passes in the correct value, compares it correctly and then breaks at the correct point, but is unable to process the return value of true?
please help?
Upvotes: 2
Views: 3380
Reputation: 1079
Just a small example that I tested to work. I dont know the content of e2Read so I made just a dummy
#ifndef UCHAR
typedef unsigned char UCHAR;
#endif
#ifndef BYTE
typedef char BYTE;
#endif
#ifndef TRUE
#define TRUE ((UCHAR)1)
#endif
#ifndef FALSE
#define FALSE ((UCHAR)0)
#endif
int e2Read(int myconst, BYTE* data, int num)
{
int i;
for(i=0;i<num;i++)
*(data++) = 0; // You can change thisone to test different results.
return 1;
}
BYTE e2CheckPINoverride(BYTE *p)
{
#define E2_ENABLECODE 3
BYTE data[5];
if(e2Read(E2_ENABLECODE, data, 5)) {
if(data[0] != p[0]) return FALSE;
if(data[1] != p[1]) return FALSE;
if(data[2] != p[2]) return FALSE;
if(data[3] != p[3]) return FALSE;
if(data[4] != p[4]) return FALSE;
}
return TRUE;
}
int main(void)
{
BYTE b[5] = {0,0,0,0,0};// You can change thisone to test different results.
BYTE* pinEntry = b;
if (e2CheckPINoverride(pinEntry) == 1){
printf("Returned true\n");
}
else{
printf("Returned false\n");
}
return 0;
}
Upvotes: 0
Reputation: 490148
IMO, you're creating a great deal of unnecessary complexity. I'd write the function something like this:
int e2CheckPINoverride(BYTE *p) {
BYTE data[5];
return e2Read(E2_ENABLECODE, data, 5) &&
data[0] == p[0] &&
data[1] == p[1] &&
data[2] == p[2] &&
data[3] == p[3] &&
data[4] == p[4];
}
And the calling code becomes simply:
PTDD_PTDD1 = e2CheckPINoverride(pinEntry);
Upvotes: 1
Reputation: 19905
If you return TRUE
or FALSE
, you should also check for them. Rewrite the if
clause like this:
if (e2CheckPINoverride(pinEntry) == TRUE) { // instead of '== 1'
Upvotes: 1
Reputation: 7937
Your data array is never initialised so it has random values inside.
BYTE data[5];
So, you are comparing the elements from array p with random values from array data. It will return almost always FALSE.
Conclusion: Fill the data array with meaningful data.
Upvotes: -1
Reputation: 27900
Try narrowing this down by dispensing with the #define and just saying
return 1;
If that works, then something isn't working with your #define's.
Upvotes: 1
Reputation: 7821
Probably not going to solve your problem, but you should write:
PTDD_PTDD1 = e2CheckPINoverride(pinEntry) ? 1 : 0;
Also, you are mixing BYTEs and UCHARs (even though they are probably the same)
Upvotes: 2
Reputation: 37147
#define TRUE 1
#define FALSE 0
Forget the unsigned char. You can go with the premise that in c 0 is false everything else is true
Upvotes: 4