CODEWITHSUNDEEP
python
genocide_in_hell
genocide_in_hell

Reputation: 11

How to split a list item in python

Suppose, I have a list like the following:

names= ["my name xyz","your name is abc","her name is cfg zyx"]

I want to split them like following:

my_array[0]= ["my","name","xyz"]
my_arrray[1]= ["your","name","is","abc"]
my_array[2]= ["her","name","is","cfg","zyx"]

So that I can choose the words individually like following:

my_array[0][0]= my
my_array[0][1]= name
my_array[1][2]= is
my_array[0][2]= xyz

The python code i tried is following:

names_abc= names.splitlines(True)
#print(names_abc)

i=0
while i < len(names_abc):
    my_array= names_abc[i].split()
    print(my_array[0])
    i=i+1

But this code doesn't do what I expect. It splits the list but cannot choose the words individually. For example, the output of the above code is following:

my your her

which is definitely wrong. I will be grateful to get a help from the python experts. Thanks in advance.

Upvotes: 1

Views: 11895

Answers (3)

unutbu
unutbu

Reputation: 880827

You could define my_array using a list comprehension:

my_array = [phrase.split() for phrase in names]

which is equivalent to

my_array = list()
for phrase in names:
    my_array.append(phrase.split())

Demo:

In [21]: names= ["my name xyz","your name is abc","her name is cfg zyx"]

In [22]: my_array = [phrase.split() for phrase in names]

In [23]: my_array
Out[23]: 
[['my', 'name', 'xyz'],
 ['your', 'name', 'is', 'abc'],
 ['her', 'name', 'is', 'cfg', 'zyx']]

In [24]: my_array[0][1]
Out[24]: 'name'

One problem with defining my_array this way:

while i < len(names_abc):
    my_array= names_abc[i].split()

is that my_array is assigned to a new list each time through the while-loop. So my_array does not become a list of lists. Instead, after the while-loop, it only retains its last value.

Instead of printing my_array[0], try print(my_array) itself. It might become more clear why you're getting the result you were getting.

Upvotes: 5

Amduscias
Amduscias

Reputation: 19

I would create a new list and fill it with lists containing temporaray strings build from the characters of your starting list.

The temporary string is ended by the space, when a string is complete it is added to a temoprary list (list_tmp).

After all items are processed as strings and added to the temporary list, we append that list the final list:

a=["my name xyz","your name is abc","her name is cfg zyx"]

l=[]

for i in enumerate(a):
        tmp_str = ''
        list_tmp=[]
        for j in i[1]:
                if " " in j:
                        list_tmp.append(tmp_str)
                        tmp_str=''
                else:
                        tmp_str+=j
        else:
                list_tmp.append(tmp_str)

        l.append(list_tmp)

print l
print l[0][1]

Upvotes: 0

Cory Kramer
Cory Kramer

Reputation: 118011

You could split() every element in your list, which by default will split on spaces.

>>> names= ["my name xyz","your name is abc","her name is cfg zyx"]
>>> [i.split() for i in names]
[['my', 'name', 'xyz'], ['your', 'name', 'is', 'abc'], ['her', 'name', 'is', 'cfg', 'zyx']]

Upvotes: 2

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