Reputation: 71
I have a function as below, which creates a strong password, however it does not always add a special character and a number or a capital letter to it, how do i ensure that it always has these requirements included in it.
The password requirements are that it has to
8 or more characters long and has to have a special character,a capital letter and a number included to it.
the function i have right now is displayed below
function GenPwd(nMinimumLength,bIsRequired,sNameoftheButton){
var end=0;
var index=0;
var sPassCharactersWithoutSpeacil="!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ";
var sSpecialCharacters="!#$@*";
var nSrngLen=sStrgStrAddOnChrs
var sNumbers="123456789";
var nMinimunLen=Math.round(nBaseLen/2);
var PassWordDLength=Math.round((Math.random()*nMinLen)+nMinimumLength+nMinimumLength); //Make sure it is atleadt 8 characters long
var Password="";
var PasswordTemporary="";
for(index = 1; index <= PassWordDLength; index++) {
nCharacter = Math.round(Math.random()*65);
PasswordTemporary = sPassCharactersWithoutSpeacil.charAt(nCharacter);
while (PWD.indexOf(PasswordTemporary) > -1) {
nCharacter = '';
nCharacter = Math.round(Math.random()*65);
PasswordTemporary = sPassCharactersWithoutSpeacil.charAt(nChar);
}
FinalPWD = Password + PasswordTemporary;
}
this is what i have to use
function GenPwd(nBaseLen,bIsStrong,sBtnName){
var end=0;
var index=0;
var sPassStr="!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ";
var sStrgStrAddOnChrs="!#$@*";
var nSrngLen=sStrgStrAddOnChrs
var sStrgStrAddOnNum="123456789";
var nMinLen=Math.round(nBaseLen/2);
var PWDLen=Math.round((Math.random()*nMinLen)+nBaseLen);
var PWD="";
var PWDTmp="";
//Generate the password
for(index = 1; index <= PWDLen; index++) {
nChar = Math.round(Math.random()*65);
PWDTmp = sPassStr.charAt(nChar);
while (PWD.indexOf(PWDTmp) > -1) {
nChar = '';
nChar = Math.round(Math.random()*65);
PWDTmp = sPassStr.charAt(nChar);
}
PWD = PWD + PWDTmp;
}
document.getElementById("pwd").value=PWD;
EnableBtn(sBtnName);
return true;
}
Upvotes: 4
Views: 757
Reputation: 707406
You can create a function that ensures your pwd contains at least one of a specific set of chars:
function ensurePwdContains(pwd, regexListOfChars, listOfChars) {
if (!regexListOfChars.test(pwd)) {
// select random char from listOfChars
var newChar = listOfChars.charAt(Math.floor(Math.random() * listOfChars.length));
// insert it into the current pwd in a random location
// must do +1 to include the location at the end of the string
var pos = Math.floor(Math.random() * (pwd.length + 1));
pwd = pwd.slice(0, pos) + newChar + pwd.slice(pos);
}
return pwd;
}
This function will test to see if the password contains at least one instance of the regex passed in. If not, it will select a random character from the listOfChars
argument and then insert that into the existing password in a random location.
And, then you call this function at the end of your function for each of your two cases:
FinalPwd = ensurePwdContains(FinalPwd, /[!#\$@*]/, sSpecialCharacters);
FinalPwd = ensurePwdContains(FinalPwd, /[A-Z]/, "ABCDEFGHIJKLMNOPQRSTUWXYZ");
Demo: http://jsfiddle.net/jfriend00/ur9FL/
And, here's a cleaned up version of your overall implementation. You were referring to a number of variables in your function that either aren't defined in your post or aren't used in your function so I removed those (since I don't know what they are or how they're used). Here's a bit cleaner implementation:
function generatePwd(minLen) {
// create a pwd that is between minLen and ((2 * minLen) + 2) long
// don't repeat any characters
// require at least one special char and one capital char
function rand(max) {
return Math.floor(Math.random() * max);
}
function ensurePwdContains(pwd, regexListOfChars, listOfChars) {
if (!regexListOfChars.test(pwd)) {
var newChar = listOfChars.charAt(rand(listOfChars.length));
var pos = rand(pwd.length + 1);
pwd = pwd.slice(0, pos) + newChar + pwd.slice(pos);
}
return pwd;
}
var legalChars = "!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ";
var specialChars = "!#$@*";
var specialRegex = /[!#\$@*]/;
var caps = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
var capsRegex = /[A-Z]/;
var nums = "123456789";
var numRegex = /[1-9]/;
// make legalChars into an array of chars (easier to deal with)
legalChars = legalChars.split("");
var pwd = "", len = minLen + rand(minLen), index;
// ensure len is not too long
len = Math.min(legalChars.length, len);
// now add chars to the pwd string until it is of the desired length
while (pwd.length < len) {
index = rand(legalChars.length);
pwd += legalChars[index];
// remove the char we just used
legalChars.splice(index, 1);
}
// ensure we have at least one special character and one caps char and one 1-9
pwd = ensurePwdContains(pwd, specialRegex, specialChars);
pwd = ensurePwdContains(pwd, capsRegex, caps);
pwd = ensurePwdContains(pwd, numRegex, nums);
return pwd;
}
And, a working demo that generates a whole bunch of passwords so you can see what type of variation you get: http://jsfiddle.net/jfriend00/7dReY/
To put the password into place, I'd suggest you make a second function that calls the first function to generate the password and puts it into the field of choice:
function putPasswordInPlace(pwdId, sBtnName) {
var pwd = generatePwd(8);
document.getElementById(pwdId).value = pwd;
EnableButton(sBtnName);
}
Upvotes: 3