Reputation: 567
If I have a vector, c(1,2,3,5,7,9,10,12)...and another vector c(3,7,10), how would I produce the following:
[[1]]
1,2,3
[[2]]
5,7
[[3]]
9,10
[[4]]
12
Notice how 3 7 and 10 become the last number of each list element (except the last one). Or in a sense the "breakpoint". I am sure there is a simple R function I am unknowledgeable of or having loss of memory.
Upvotes: 3
Views: 1567
Reputation: 92300
Could do
split(x, cut(x, unique(c(y, range(x)))))
## $`[1,3]`
## [1] 1 2 3
## $`(3,7]`
## [1] 5 7
## $`(7,10]`
## [1] 9 10
## $`(10,12]`
## [1] 12
Upvotes: 1
Reputation: 14366
Similar to @beginneR 's answer, but using findInterval
instead of cut
split(x, findInterval(x, y + 1))
# $`0`
# [1] 1 2 3
#
# $`1`
# [1] 5 7
#
# $`2`
# [1] 9 10
#
# $`3`
# [1] 12
Upvotes: 0
Reputation: 70336
Here's one way using cut
and split
:
split(x, cut(x, c(-Inf, y, Inf)))
#$`(-Inf,3]`
#[1] 1 2 3
#
#$`(3,7]`
#[1] 5 7
#
#$`(7,10]`
#[1] 9 10
#
#$`(10, Inf]`
#[1] 12
Upvotes: 3