CODEWITHSUNDEEP
pythonemailsmtp
Zach
Zach

Reputation: 5073

Trying to send email through GoDaddy using Python

Here is the code I am using to send email through GoDaddy:

import smtplib

server = smtplib.SMTP('smtpout.secureserver.net', 465)
server.starttls()
server.ehlo()
server.login("username", "password")
msg = "Please work!!!!!!"
fromaddr = "fromemail"
toaddr = "toemail"
server.sendmail(fromaddr, toaddr, msg)

When running the script, I get this error:

Traceback (most recent call last):
File "emailTest.py", line 3, in <module>
server = smtplib.SMTP('smtpout.secureserver.net', 465)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/smtplib.py",      line 250, in __init__
(code, msg) = self.connect(host, port)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/smtplib.py", line 311, in connect
(code, msg) = self.getreply()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/smtplib.py", line 362, in getreply
raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closed

I'm really lost on this one, and I know for a fact that my login information is correct.

Upvotes: 1

Views: 7376

Answers (4)

Joe
Joe

Reputation: 161

If anyone is having problems with RFC 5322 compliant emails this ended up working for me:

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

msg = MIMEMultipart()
msg.set_unixfrom('author')
msg['From'] = '[email protected]'
msg['To'] = '[email protected]'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP_SSL('smtpout.secureserver.net', 465)
mailserver.ehlo()
mailserver.login('[email protected]', 'PASSWORD')

mailserver.sendmail('[email protected]','[email protected]',msg.as_string())

mailserver.quit()

Upvotes: 7

Sanjeev Das
Sanjeev Das

Reputation: 1

Here is the overall code that works.

import smtplib`enter code here`
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

msg = MIMEMultipart()
msg.set_unixfrom('author')
msg['From'] = 'your email'
msg['To'] = '[email protected]'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP_SSL('smtpout.secureserver.net', 465)
mailserver.ehlo()
mailserver.login('your email', 'password')
response = mailserver.sendmail('[email protected]','[email protected]',msg.as_string())
mailserver.quit()

Upvotes: 0

TBone
TBone

Reputation: 305

Joe's code worked for me. The only thing i had to change were the import statements:

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

Then everything worked! Thanks, Joe.

(Sorry I couldn't leave this as a comment or upvote it - my reputation isn't high enough to comment yet.)

Upvotes: 2

Robᵩ
Robᵩ

Reputation: 168646

Replace these two lines:

server = smtplib.SMTP('smtpout.secureserver.net', 465)
server.starttls()

with these two:

server = smtplib.SMTP_SSL('smtpout.secureserver.net', 465)
#server.starttls()

Quoting the doc:

SMTP_SSL should be used for situations where SSL is required from the beginning of the connection and using starttls() is not appropriate.

Using port 465 is one of those situations. SMTP.starttls() is appropriate when you use port 25 or port 587.

References:

Upvotes: 5

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