Reputation: 24121
I have a symmetric m
-by-m
matrix A
. Each element has a value between 0 and 1. I now want to choose n
rows / columns of A
which form an n
-by-n
sub-matrix B
.
The criteria for choosing these elements, is that the sum of all elements of B
must be the minimum out of all possible n
-by-n
sub-matrices of A
.
For example, suppose that A
is a 4-by-4 matrix:
A = [0 0.5 1 0; 0.5 0 0.5 0; 1 0.5 1 1; 0 0 1 0.5]
And n
is set to 3. Then, the best B
is the one taking the first, second and fourth rows / columns of A
:
B = [0 0.5 0; 0.5 0 0; 0 0 0.5]
Where the sum of these elements is 0 + 0.5 + 0 + 0.5 + 0 + 0 + 0 + 0 + 0.5 = 1.5, which is smaller than another other possible 3-by-3 sub-matrices (e.g. using the first, third and fourth rows / columns).
How can I do this?
This is partly a mathematics question, and partly a Matlab one. Any help with either would be great!
Upvotes: 3
Views: 1009
Reputation: 797
Do the following:
m = size(A,1);
n=3;
sub = nchoosek(1:m,n); % (numCombinations x n)
subR = permute(sub,[2,3,1]); % (n x 1 x numCombinations), row indices
subC = permute(sub,[3,2,1]); % (1 x n x numCombinations), column indices
lin = bsxfun(@plus,subR,m*(subC-1)); % (n x n x numCombinations), linear indices
allB = A(lin); % (n x n x numCombinations), all possible Bs
sumB = sum(sum(allB,1),2); % (1 x 1 x numCombinations), sum of Bs
sumB = squeeze(sumB); % (numCombinations x 1), sum of Bs
[minB,minBInd] = min(sumB);
fprintf('Indices for minimum B: %s\n',mat2str(sub(minBInd,:)))
fprintf('Minimum B: %s (Sum: %g)\n',mat2str(allB(:,:,minBInd)),minB)
This looks only for submatrices where the row indices are the same as the column indices, and not necessarily consecutive. That is how I understood the question.
Upvotes: 4
Reputation: 4558
Try to convolve the matrix A
with a smaller matrix M
. Eg if you is interested in finding the 3x3 submatrix then let M
be ones(3)
. This code shows how it works.
A = toeplitz(10:-1:1) % Create a to eplitz matrix (example matrix)
m = 3; % Submatrix size
mC = ceil(m/2); % Distance to center of submatrix
M = ones(m);
Aconv = conv2(A,M); % Do the convolution.
[~,minColIdx] = min(min(Aconv(1+mC:end-mC,1+mC:end-mC))); % Find column center with smallest sum
[~,minRowIdx] = min(min(Aconv(1+mC:end-mC,minColIdx+mC),[],2)); % Find row center with smlest sum
minRowIdx = minRowIdx+mC-1 % Convoluted matrix is larger than A
minColIdx = minColIdx+mC-1 % Convoluted matrix is larger than A
range = -mC+1:mC-1
B = A(minRowIdx+range, minColIdx+range)
The idea is to imitate a fir filter y(n) = 1*x(n-1)+1*x(n)+1*x(n+1)
. For now it only finds the first smallest matrix though. Notice the +1 adjustment because first matrix element is 1. Then notice the the restoration right below.
Upvotes: 1
Reputation: 423
This is a bit brute force, but should work
A = [0 0.5 1 0; 0.5 0 0.5 0; 1 0.5 1 1; 0 0 1 0.5];
sizeA = size(A,1);
size_sub=3;
idx_combs = nchoosek(1:sizeA, size_sub);
for ii=1:size(idx_combs,1)
sub_temp = A(idx_combs(ii,:),:);
sub = sub_temp(:,idx_combs(ii,:));
sum_temp = sum(sub);
sums(ii) = sum(sum_temp);
end
[min_set, idx] = min(sums);
sub_temp = A(idx_combs(idx,:),:);
sub = sub_temp(:,idx_combs(idx,:))
Upvotes: 1