CODEWITHSUNDEEP
xsltsaxon
Wojtek
Wojtek

Reputation: 1530

How do I define the default XPath namespace in Saxon 9.5 EE in Java code?

How do I define the equivalent of the xpath-default-namespace, for example:

<xsl:stylesheet version="2.0" xpath-default-namespace="http://schemas.xmlsoap.org/soap/envelope/"

in the following Java code snippet for Saxon EE 9.5?

public String transform(String request) {
    try {
        ProfessionalConfiguration config = new ProfessionalConfiguration();
        config.setExtensionElementNamespace("http://yeah.com", "com.MyFactory");
        config.registerExtensionFunction(new MyVariable());

        EnterpriseTransformerFactory factory = new EnterpriseTransformerFactory();
        factory.setConfiguration(config);

        Source xslt = new StreamSource(new File("text.xsl"));
        Transformer transformer = factory.newTransformer(xslt);

        Source input = new StreamSource(new File("test.xml"));
        StringWriter result = new StringWriter();
        transformer.transform(input, new StreamResult(result));

        return result.toString();
    } catch (Exception e) {
        throw new RuntimeException(e);
    }
}

Upvotes: 0

Views: 420

Answers (1)

Michael Kay
Michael Kay

Reputation: 163322

You can't change the default xpath namespace from your Java code, only from your XSLT code.

You say you can't edit the XSLT stylesheets but you can. They are XML documents and can be transformed, and you have a transformation language and transformation engine available to you. If there's no other way of solving this, transform the stylesheets before executing them.

Upvotes: 1

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