linello
linello

Reputation: 8694

cvxopt can't solve a simple linear optimization

I have this model

 min c' x
 s.t.
 G x <= h
 x are integers or binary variables

where c is a 16x1 numpy array of coefficients, G is a 12 x 16 matrix that represents the constraints of the model and h is 12x1 array of ones.

::::::::::::::
c
::::::::::::::
-0.00
-0.38
0.12
0.12
-0.38
-0.00
0.12
0.12
0.12
0.12
-0.00
-0.38
0.12
0.12
-0.38
-0.00
::::::::::::::
G
::::::::::::::
0 1 -1 0 0 0 1 0 0 0 0 0 0 0 0 0
0 1 1 0 0 0 -1 0 0 0 0 0 0 0 0 0
0 -1 1 0 0 0 1 0 0 0 0 0 0 0 0 0
0 1 0 -1 0 0 0 1 0 0 0 0 0 0 0 0
0 1 0 1 0 0 0 -1 0 0 0 0 0 0 0 0
0 -1 0 1 0 0 0 1 0 0 0 0 0 0 0 0
0 0 1 -1 0 0 0 0 0 0 0 1 0 0 0 0
0 0 1 1 0 0 0 0 0 0 0 -1 0 0 0 0
0 0 -1 1 0 0 0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 1 -1 0 0 0 1 0 0 0 0
0 0 0 0 0 0 1 1 0 0 0 -1 0 0 0 0
0 0 0 0 0 0 -1 1 0 0 0 1 0 0 0 0
::::::::::::::
h
::::::::::::::
1
1
1
1
1
1
1
1
1
1
1
1

From the cvxopt documentation I'd think that the model should be implemented as a linear program and be solved with lp solver

cvxopt.solvers.lp(c=cvxopt.matrix(c), G=cvxopt.matrix(G), h=cvxopt.matrix(h) )

but I get this error:

/usr/local/lib/python2.7/dist-packages/cvxopt/coneprog.pyc in lp(c, G, h, A, b, solver, primalstart, dualstart)
   3006 
   3007     return conelp(c, G, h, {'l': m, 'q': [], 's': []}, A,  b, primalstart,
-> 3008         dualstart)
   3009 
   3010 

/usr/local/lib/python2.7/dist-packages/cvxopt/coneprog.pyc in conelp(c, G, h, dims, A, b, primalstart, dualstart, kktsolver, xnewcopy, xdot, xaxpy, xscal, ynewcopy, ydot, yaxpy, yscal)
    572     if kktsolver in defaultsolvers:
    573         if b.size[0] > c.size[0] or b.size[0] + cdim_pckd < c.size[0]:
--> 574            raise ValueError("Rank(A) < p or Rank([G; A]) < n")
    575         if kktsolver == 'ldl':
    576             factor = misc.kkt_ldl(G, dims, A, kktreg = KKTREG)

ValueError: Rank(A) < p or Rank([G; A]) < n

while using the glpk interface of cvxopt actually works smoothly and it gives me good solutions:

(status, sol) = cvxopt.glpk.ilp(c=cvxopt.matrix(c),   # c parameter
                                G=cvxopt.matrix(G),     # G parameter
                                h=cvxopt.matrix(h),     # h parameter
                                I=set(range(0, len(c))),
                                B=set(range(0, len(c)))
                                )

How can I make lp solver work in cvxopt for this problem?

Upvotes: 0

Views: 5423

Answers (1)

Angela
Angela

Reputation: 53

I am not entirely sure, but I think, the problem is more a mathematical problem than based on the code.

The dimensions of your matrices are c is 16 x 1, G is 16 x 12 and h is 12 x 1. But the rank of matrix G is much lower. In fact, on ten of the 16 entries of x there are no constraints. To the program, it is an infeasible solution as the minimum would be minus infinity.

E.g. for x[14] are no constraints in G and h, it could be any value. In the minimizing function c[14] = -0.38, therefore a minimizing value would be x[14] = +inf which gives the solution -inf = min c'x

This is the explanation of the error as you described it:

ValueError: Rank(A) < p or Rank([G; A]) < n

This part of code appears at different parts and usually checks the dimension of the problem and determines, whether there are enough constraints to solve the problem.

I solved the problem but omitted any unconstrained values of x. The result is still unfeasible, but that might be due to the constraints or some other error...

[Previous definition of the matrices]
>>> index = [1,2,3,6,7,11]
>>> c = c[index]
>>> G = G[::,index]
>>> cv.solvers.lp(c=c, G=G, h=h )
     pcost       dcost       gap    pres   dres   k/t
 0: -2.8000e-01 -1.3000e+01  1e+01  1e+00  5e+00  1e+00
 1: -1.7954e-01 -1.6503e+00  1e+00  1e-01  6e-01  7e-03
 2:  1.0328e-01 -1.5888e+01  1e+03  1e+00  6e+00  8e-01
 3: -1.1620e+01 -3.8498e+00  5e+03  3e-01  1e+00  1e+01
 4: -1.1605e+03 -3.8498e+00  5e+05  3e-01  1e+00  1e+03
 5: -1.1604e+05 -3.8498e+00  5e+07  3e-01  1e+00  1e+05
 6: -1.1604e+07 -3.8498e+00  5e+09  3e-01  1e+00  1e+07
 7: -1.1604e+09 -3.8498e+00  5e+11  3e-01  1e+00  1e+09
 Certificate of dual infeasibility found.
{'status': 'dual infeasible', 'dual slack': None, 'iterations': 7, 'residual as primal
infeasibility certificate': None, 'relative gap': None, 'dual objective': None, 
'residual as dual infeasibility certificate': 1.1035651154462114e-09, 'gap': None, 
's': <12x1 matrix, tc='d'>, 'primal infeasibility': None, 'dual infeasibility': None, 
'primal objective': -1.0, 'primal slack': 94.0289560690342, 'y': None, 'x': <6x1 
matrix, tc='d'>, 'z': None}

Feel free to correct me, if I'm wrong.

Upvotes: 0

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