CODEWITHSUNDEEP
python
user3776356
user3776356

Reputation: 41

Python, counting from an inputted string. Needs to be returned in a specific order?

So i am typing a code where a user will need to input >>Count('bla bla bla') and the program needs to count the in the bla bla bla phrase and return the word with its count in this SPECIFIC order.

Any Help?

Upvotes: 0

Views: 71

Answers (4)

Pankaj Sharma
Pankaj Sharma

Reputation: 679

def vowelCount(text):
    vowels = 'aeiou'
    return ("a, e, i, o, and u appear, respectively, %s times." %", ".join([ str(text.count(x)) for x in vowels]))

print vowelCount('bla bla bla')

Hope this helps.

Upvotes: 1

Ashalynd
Ashalynd

Reputation: 12573

You made a typo:

def vowelCount(text):
    vowels = 'aeiou'
    counts = {x:text.count(x) for x in vowels}
    keys = counts.keys()
    values = counts.values()
    return ','.join(keys[:-1]) + ' and '+ keys[-1] +' appear, respectively, '+ ','.join(str(v) for v in values)+' times.'

Upvotes: 0

Mark Whitfield
Mark Whitfield

Reputation: 2528

The code as written doesn't even examine the input text at all. You're counting the number of times each vowel appears in vowels.

Replace with text.count(i) instead of vowels.count(i).

Upvotes: 0

Cory Kramer
Cory Kramer

Reputation: 117981

Your count function is not used correctly. You want text.search(vowel), not vowel.search(text)

>>> s = 'this is some string with a lot of vowels'
>>> vowels = 'aeiou'
>>> {i : s.count(i) for i in vowels}
{'a': 1, 'i': 4, 'e': 2, 'u': 0, 'o': 4}

Dictionaries have no order, so if you want the count in vowel order:

>>> [(i,s.count(i)) for i in vowels]
[('a', 1), ('e', 2), ('i', 4), ('o', 4), ('u', 0)]

Upvotes: 5

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