Reputation: 38
I was wondering if it was possible to have a Java dictionary of objects where one of the fields of the object is defined to be the key of the dictionary.
To be more specific, here's what I would like: I have defined a class with three fields. One of these fields is an Integer and is unique to each object. I would like this field to be the key of the dictionary.
Upvotes: 0
Views: 1041
Reputation: 86774
If you want to hide the details:
public interface HasOwnKey<K> {
public K getKey();
}
public class MyMap<K, V extends HasOwnKey<K>> {
{
private Map<K,V> map = new HashMap<>();
public V put(V value) {
{
return this.map.put(value.getKey(),value);
}
public V get(K key) {
return this.map.get(key)
}
... etc
}
public class MyClass extends HasOwnKey<String> {
...
@Override String getKey() { return this.key; }
}
MyMap<String, MyClass> myMap = new MyMap<>();
MyClass obj = new MyClass();
obj.setKey("abc");
myMap.put(obj);
Unfortunately Java 7 doesn't seem to be smart enough to infer K
from a declaration like
public class MyMap<V extends HasOwnKey<K>> {
so you have to provide the Key type in two places and cannot do
MyMap<MyClass> myMap = new MyMap<>();
Upvotes: 1
Reputation: 1367
If you already have created a List of those objects you can use an aggregate operation in java 8 like this:
Map<Integer, List<MyClass>> theMap = list
.stream()
.collect( Collectors.groupingBy(MyClass::myIntegerKey) );
Upvotes: 0
Reputation: 7728
You can do that easily as follows :
public class CustomClass
{
private int primaryKey;
private int secondaryField;
private int tertiaryField;
public CustomClass(int primaryKey, int secondaryField, int tertiaryField)
{
this.primaryKey = primaryKey;
this.secondaryField = secondaryField;
this.tertiaryField = tertiaryField;
}
public int getPrimaryKey(CustomClass object)
{
return object.primaryKey;
}
}
public class Test
{
public static void main(String[] args)
{
CustomClass object = new CustomClass(10, 20, 30);
Map map = new HashMap<Integer,CustomClass>();
map.put(object.getPrimaryKey(object), object);
}
}
You may also want to consider using Enums
for doing the same, if the number of such records is fairly less, as they provide more readability.
Upvotes: 0
Reputation: 393841
Yes, of course it's possible.
Example :
Map<Integer,MyClass> map = new HashMap<Integer,MyClass>();
MyClass myObject = new MyClass(...);
map.put (myObject.getIntegerKey(), myObject);
Upvotes: 2