CODEWITHSUNDEEP
filegrepecho
stevo
stevo

Reputation: 181

bash grep file directories

I want to grep 'run' numbers in some files e.g.

files/run3/testlog
files/run14/testlog
files/run28/testlog

I have the following code:

for f in $(find . -name testlog)
do
     echo $(pwd) | egrep -o run[0-9]{*}
done

I want my code to output:

run3
run14
run28

However I am not getting any output.

Upvotes: 0

Views: 88

Answers (3)

Jonas Raedle
Jonas Raedle

Reputation: 118

I think the problem are the curly brackets around *, just try egrep -o run[0-9]*.

If you don't want to match "run", try egrep -o run[0-9]+.

Upvotes: 1

Oleg Gryb
Oleg Gryb

Reputation: 5249

Try this:

for f in $(find . -name testlog)
do
     echo $(basename $(dirname $f))
done

Upvotes: 0

eckes
eckes

Reputation: 10423

You need to replace ${pwd} with $f and should quote the regular expression.

I would use sed and avoid the for loop (but you can also use grep -o, if you use the pattern correctly, i.e. without braces)

find . -name testlog -print | sed -n 's/.*\/\(run[0-9]*\)\/testlog/\1/p'

or

find . -name testlog -print | grep -o 'run[0-9]+'

Upvotes: 0

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