CODEWITHSUNDEEP
bashfor-loopexecutable
gabboshow
gabboshow

Reputation: 5559

execute program in loop bash script

I would like to run the executable run_ex multiple times varying some parameters (text file), but I am new to the bash scripts and I can't figure out how to do that...

#! /bin/bash
for ((hour=1; hour <= 9 ; hour++))
do
   printf "run executable for hour %d \n" $hour

   parameter1 ="/path1/file1_$hour.txt" 

   parameter2 = "/path2/file2_$hour.txt" 

   ./run_ex $parameter1 $parameter2

done

Thanks

Upvotes: 0

Views: 4466

Answers (2)

konsolebox
konsolebox

Reputation: 75488

Following Sylvain Leroux's answer, you should also place your variables inside double-quotes to prevent word splitting and unexpected pathname expansion:

#!/bin/bash
for ((hour=1; hour <= 9 ; hour++))
do
    printf "run executable for hour %d \n"" $hour"

    parameter1="/path1/file1_$hour.txt" 
    parameter2="/path2/file2_$hour.txt" 

   ./run_ex "$parameter1" "$parameter2"
done

Also with brace expansion, you can simplify for ((hour=1; hour <= 9 ; hour++)) as for hour in {1..9}; do.

See Word Splitting and Pathname or Filename Expansion.

Upvotes: 1

Sylvain Leroux
Sylvain Leroux

Reputation: 52000

spaces are not allowed around = for variable assignment:

  parameter1 ="/path1/file1_$hour.txt" 
  #         ^

Write that instead:

  parameter1="/path1/file1_$hour.txt" 
  parameter2="/path2/file2_$hour.txt"

Upvotes: 3

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