Reputation: 21
A have query: "SELECT date, COUNT(id) FROM leads WHERE userkey = '$userkey' GROUP BY DAY(date)"
I want add second where is_lead 1
Example:
[FIRST]
SELECT date, COUNT(id) FROM leads WHERE userkey = '$userkey' GROUP BY DAY(date)
[SECOND]
SELECT COUNT(price) from leads WHERE userkey = '$userkey' and is_lead = 1
Union not work.
Please Help!
Upvotes: 1
Views: 70
Reputation: 660
or you want to do this?
SELECT a.userkey,DATE, COUNT(id),b.countp
FROM leads a
LEFT JOIN (SELECT COUNT(price) AS countp
FROM leads
WHERE userkey = '$userkey' AND is_lead = 1) b
ON a.userkey=b.userkey
WHERE userkey = '$userkey'
GROUP BY DAY(DATE)
Upvotes: 2