CODEWITHSUNDEEP
pythonpython-3.xprintinggenerator
nobody
nobody

Reputation: 414

python 3 print generator

There is a problem when i deal with print() function(Python 3).

When I'm looking for sum of a series I may use the following code pattern:

>>> sum(i for i in range(101))

But when I tend to check the series that I had made: (I choose print() and assume it will print out line by line)

>>> print(i for i in range(101))

It turns out become a generator object without value return. So I have to used list() for series checking. Is that a flaw in print function?

PS: The above written is an example to form a generator, not the simplest form for natural series but the bone structure for complex series. In order for convenience in series values checking, I am looking for a way to print out each value line by line.

Upvotes: 8

Views: 5568

Answers (2)

mgilson
mgilson

Reputation: 309899

This behavior isn't too much different than on python2.x:

Python 2.7.5 (default, Mar  9 2014, 22:15:05) 
[GCC 4.2.1 Compatible Apple LLVM 5.0 (clang-500.0.68)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>>
>>> print (i*i for i in range(30))
<generator object <genexpr> at 0x10c034a50>

Generally speaking, if you want to actually know the items, a list might be easiest (it just requires the addition of a couple square brackets:

print [i*i for i in range(30)]

or on python3.x:

print([i*i for i in range(30)])

Upvotes: 1

user2357112
user2357112

Reputation: 280544

sum takes an iterable of things to add up, while print takes separate arguments to print. If you want to feed all the generator's items to print separately, use * notation:

print(*(i for i in range(1, 101)))

You don't actually need the generator in either case, though:

sum(range(1, 101))
print(*range(1, 101))

If you want them on separate lines, you're expecting the behavior of multiple individual calls to print, which means you're expecting the behavior of a regular loop:

for item in generator_or_range_or_whatever:
    print(item)

though you also have the option of specifying '\n' as an item separator:

print(*generator_or_range_or_whatever, sep='\n')

Upvotes: 14

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