Reputation: 47
Here's my code:
import easygui
f = easygui.fileopenbox()
print f
Seems simple, but when I run it, I can't select any of the files, see figure in link. Sorry if this is dumb, but I am at my wit's end!
https://i.sstatic.net/A0otI.jpg
Upvotes: 2
Views: 3261
Reputation: 4955
EasyGui isn't supported anymore. On OS X I don't have this problem with fileopenbox
(it looks like what happens with diropenbox
actually.) I'd recommend you try something like wxPython. Here's how to get a file open box in that (from https://stackoverflow.com/a/9319832/866271)
import wx
def get_path(wildcard):
app = wx.App(None)
style = wx.FD_OPEN | wx.FD_FILE_MUST_EXIST
dialog = wx.FileDialog(None, 'Open', wildcard=wildcard, style=style)
if dialog.ShowModal() == wx.ID_OK:
path = dialog.GetPath()
else:
path = None
dialog.Destroy()
return path
print get_path('*.txt')
Tested on OS X with no problem. It's also cross-platform. If you're going to be doing GUI development, there's a lot of options to look at but wxPython is a good one because it uses the native widgets of whatever OS you're running. So everything looks pretty :)
For your case, you could instead call get_path('*.csv')
if that's the type of file you're opening. Or just call get_path('*')
to get all of them.
Upvotes: 2