CODEWITHSUNDEEP
c#linqlistaveragemontecarlo
Hooplator15
Hooplator15

Reputation: 1550

How to average a List<List<double>> for each inner entry?

I am doing a MonteCarlo Simulation and am nearly finished writing the code for that part of my application. Ihave the following list:

List<List<double>> myFullList = new List<List<double>>();
List<double> myInnerList = new List<double>();

for(int i = 1; i <= numberOfLoops; i++)
{ 
    for(int i = 1; i <= 10; i++)
    {
        // Populate inner list with random numbers
        myInnerList.Add(double myRandomNumber);
    }

    // Add the inner list to the full list
    myFullList.Add(myInnerList);
}

The list should look something like this:

myFullList[0] = {rand#1,rand#2,rand#3,...,rand#10}
myFulllist[1] = {rand#1,rand#2,rand#3,...,rand#10}
.
.
.
.
myFulllist[1] = {rand#1,rand#2,rand#3,...,rand#10}

I need to average that data to form ONE single list that looks something like this:

List<double> averagedData = new List<double>();
averagedData = {avg#1, avg#2........avg#10}

This output variable will average the data for the same "row" of data in the inner list.

Simple example:

innerList[0] = {1,2,3};
innerList[1] = {3,2,1};

fullList = {innerList[0], innerList[1]};

averageList = {2,2,2};

Upvotes: 2

Views: 570

Answers (2)

Reed Copsey
Reed Copsey

Reputation: 564433

If you are just trying to average each inner list, you can use:

List<double> averagedData = myFullList.Select(l => l.Average()).ToList();

If you are trying to average the "columns" of data, which seems to be the case from your sample, you could do something like:

var averagedData = myFullList[0].Select((v,c) =>
                       myFullList.Average(r => r[c])
                  ).ToList();

Upvotes: 5

Xiaoy312
Xiaoy312

Reputation: 14477

var averagedData = myFullList.Select(x => x.Average()).ToList();

Upvotes: -2

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