CODEWITHSUNDEEP
javajson
user3409650
user3409650

Reputation: 523

How to get part of httpResponse in java

I want to get just ID from httpResponse after I did HttpGet.

This is my code:

HttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("http://localhost:80/api/");

HttpResponse httpResponse = httpClient.execute(httpGet);
System.out.println(httpResponse);
BufferedReader rd = new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent()));

String line = "";
while ((line = rd.readLine()) != null) {
  System.out.println(line);
}

which returns this:

{"list":[{"timestamp":{"$date":"2014-08-01T08:37:54.058Z"},"nameGroup":false,"_id":{"$oid":"53db5045ccf2b2399e0e6128"},"created":{"$date":"2014-08-01T08:31:01.139Z"}],"name":"John"}]}

But I just want Oid not the whole thing. Any idea?

Thanks

Upvotes: 0

Views: 292

Answers (3)

Ritesh Gune
Ritesh Gune

Reputation: 16729

I think instead of using a library just to get value of one parameter is not appropriate if you have other options available. I would suggest you to parse the json on yor own using the APIs provided. You can try following:

try {

JSONObject obj = new JSONObject(your_json_string);
String value= null; 

if (obj != null && obj.has(YOUR_KEY_FOR_PARAM)) {
                value = obj.getString(YOUR_KEY_FOR_PARAM));
} 
}

Upvotes: 0

FreakyBytes
FreakyBytes

Reputation: 181

Strint you've got is json encoded data, so you need to decode it and than you are able to access the field "oid". There are several libaries around to acomplish this job:

  • gson
  • JsonSimple
  • Jackson etc.

My favorite for small projects is gson

Upvotes: 1

Bozho
Bozho

Reputation: 597076

Using Jackson or Gson, you can parse the response JSON and get exactly the part you need.

If you don't need the whole result, then there is no point in creating a reference object, just manually traverse the json document, e.g.

mapper.readTree(responseText).get("foo").get("bar")

Upvotes: 0

Related Questions