Reputation: 257
My environment is: W7 Ultimate 64 bits, VS2010 Ultimate, C#, WinForm, target XP and W7.
With the help of @dasblinkenlight, the concatenation on the for loop was very good. I feel we are making great progress. As you ca see, we are putting into the array sMntHour[d,h] the string "csv_001_01" if d=1 and h=1 and so on.
This csv_001_01, csv_001_02,.. ; are variables that contains an integer value.
csv_001_01=5111;
csv_001_02=236; // This is a sample, because has 365 days in normal year
// and 366 days in leaf year. "csv_day_hour"
Directly we could do this:
sMntHour[d,h] = csv_001_01.ToString(); // d is day and h is hour
sMntHour[d,h] = csv_001_02.ToString();
As we put the value of this concatenated variable in the array and not the name of the variables?
for(int d=1;d<=365;d++) //I'll put the code to not leap years.
{
for(int h=1; h<=24; h++)
{
sMntHour[d,h] = string.Format("csv_{0:000}_{1:00}", d, h)
}
}
Upvotes: 2
Views: 97
Reputation: 101701
If I understand what you mean, you have all the variable names and now you want to get their values.
You could do this using Reflection
and you can create a dictionary where keys are the variable names and the values are the actual values. It is really hard to help without seeing how these variables are declared, are they fields / properties ? are the private, static ? etc... But something like this should work, in theory:
var type = this.GetType();
var values = sMntHour.OfType<string>()
.ToDictionary(
x => x,
x => (int)type.GetField(x).GetValue(this));
Then you can access the values using values["variable_name"]
Or if you don't want this, instead if you want to access them using index like [d,h]
as mentioned in comments, do not store the variable names in the first place instead store the values in your array:
var type = this.GetType();
for(int d=1;d<=365;d++)
{
for(int h=1; h<=24; h++)
{
var name = string.Format("csv_{0:000}_{1:00}", d, h);
sMntHour[d,h] = (int)type.GetField(name).GetValue(this);
}
}
Ofcourse you need to change the type of sMntHour
, in order to make it work.
Upvotes: 2