CODEWITHSUNDEEP
c
vishal
vishal

Reputation: 7

function prototype mismatch, still program runs on Visual studio 2008 and gcc compiler

Function prototype is different than call and definition; still it does not give any error on Visual studio and gcc compiler

    #include<stdio.h>

    void print(); //prototype

    void main()
    {
          print(2,2); //calling
    }

    void print(int a,int b) //definition
    {
        printf("\na=%d\tb=%d",a,b);
    }

Upvotes: 0

Views: 404

Answers (2)

BLUEPIXY
BLUEPIXY

Reputation: 40145

6.7.5.3 Function declarators (including prototypes) 14

An identifier list declares only the identifiers of the parameters of the function. An empty list in a function declarator that is part of a definition of that function specifies that the function has no parameters. The empty list in a function declarator that is not part of a definition of that function specifies that no information about the number or types of the parameters is supplied.

void print();//prototype will be considered a prototype such as having a no specified argument.

Upvotes: 0

Santosh A
Santosh A

Reputation: 5351

With the above declared function prototype,
you can pass any number of arguments to the function irrespective of the number of arguments it takes.

Like for example

#include<stdio.h>

void print();//prototype

void main()
{
      print(2,2);//calling
      print(3);           // This would also work output a = 3, b = garbage value
      print(4,5,6);       // This would also work output a = 4, b = 5
}

void print(int a,int b)//defination
{
    printf("\na=%d\tb=%d",a,b);
}

Note : If you don't want to pass any arguments to a function, it is advisable to use void like void print(void);

Upvotes: 1

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