CODEWITHSUNDEEP
c#jqueryasp.netgridview
neeraj
neeraj

Reputation: 119

dynamically add button column in Asp.net GridView using Jquery

I have populated Grid View Dynamically with json Data ..Button Column started to appears only in First Row ..But not in below rows ..

I have Tried Code to add column in server side code as well as in Mark Up ..I also search but could not able to find any thing relevant

this is my MarkUp :

  <script type="text/javascript">
        $(document).ready(function () {
            $.ajax({
                type: "POST",
                contentType: "application/json; charset=utf-8",
                url: "List.aspx/GetData",
                data: "{}",
                dataType: "json",
                success: function (data) {
                    for (var i = 0; i < data.d.length; i++) {
                        $("#gvDetails").append("<tr><td>" + data.d[i].c1 + "</td><td>" + data.d[i].c2 + "</td><td>" + "</td></tr>");
                    }
                },
                error: function (result) {
                    alert(result.status + ' ' + result.statusText);
                }
            });
        });
    </script>
</head>
<body>
    <form id="form1" runat="server">
    <div>
        <asp:GridView ID="gvDetails" runat="server" ShowHeaderWhenEmpty="True">
            <Columns>
                <asp:ButtonField Text="Button" />
            </Columns>
        </asp:GridView>
    </div>
    </form>
</body>

this is code behind :

 protected void Page_Load(object sender, EventArgs e)
        {
            BindColumnToGridview();
        }

        private void BindColumnToGridview()
        {
            DataTable dt = new DataTable();
            dt.Columns.Add("c1");
            dt.Columns.Add("c2");

            dt.Rows.Add();
            gvDetails.DataSource = dt;

            gvDetails.DataBind();

        }


        [WebMethod]
        [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
        public static tbl1[] GetData()
        {

            try
            {
                using (var context = new TestDBContext())
                {
                    List<tbl1> lsTbl1 = new List<tbl1>();

                    lsTbl1 = (from c in context.tbl1 select c).ToList();
                    return lsTbl1.ToArray();

                }
            }
            catch (Exception)
            {

                throw;
            }

        }

I also tried to add column from code behind 

gvDetails.Columns.Add(new ButtonField() { Text = "Button"  });

this is not working too

any sugestion will be helpful

Upvotes: 1

Views: 2229

Answers (1)

Aditya Singh
Aditya Singh

Reputation: 9612

Since gvDetails is a server side control you should use <%= gvDetails.ClientID %> in your JS snippet.

<script type="text/javascript">
        $(document).ready(function () {
            $.ajax({
                type: "POST",
                contentType: "application/json; charset=utf-8",
                url: "List.aspx/GetData",
                data: "{}",
                dataType: "json",
                success: function (data) {
                    for (var i = 0; i < data.d.length; i++) {
                        $("#<%= gvDetails.ClientID %>").append("<tr><td>" + data.d[i].c1 + "</td><td>" + data.d[i].c2 + "</td><td>" + "</td></tr>");
                    }
                },
                error: function (result) {
                    alert(result.status + ' ' + result.statusText);
                }
            });
        });
    </script>

EDIT:

enter image description here

Upvotes: 1

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