CODEWITHSUNDEEP
javascriptjshint
Ryan
Ryan

Reputation: 10131

Default argument in JavaScript caused jshint error

for example, my code below

(function ($) {

    window.FOO || (FOO = {});

}(jQuery));

caused jshint error:

Expected an assignment or function call and instead saw an expression.

Are there any better way to write my above code?

i.e. if FOO is not defined in global window scope, init it as {}

Upvotes: 1

Views: 182

Answers (1)

James Donnelly
James Donnelly

Reputation: 128786

Update: From comments:

I've updated the code above. I want the FOO in the global scope, i.e. window.

For that you can just set window.FOO instead:

window.FOO = window.FOO || {};

Here if window.FOO already exists its value will remain unchanged, otherwise window.FOO will be set to an empty object.

Old answer:

You need to declare the variable using var:

var FOO = window.FOO || {};

This will set the FOO variable to window.FOO if that exists or an empty object if not.

var FOO = window.FOO || {};
console.log(FOO);

> Object {}

window.FOO = "Hello, world!";
var FOO = window.FOO || {};
console.log(FOO);

> "Hello, world!"

Upvotes: 2

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