CODEWITHSUNDEEP
pythonclasspython-3.x
Landon
Landon

Reputation: 21

Comparing variables within classes in python

I'm trying to write a method(it) that compares the size (area) of the rectangle with the area of another rectangle passed as a parameter:

class Rectangle:
    def __init__(self, x, y):
       self.width = x
       self.height = y

    def area(self):
       a = self.width * self.height
       return a

    def __it__(self,second):
       return self.area < second.area

But I keep getting error:

TypeError: unorderable types: Rectangle() < Rectangle()

I'm not to sure how to fix this problem

Upvotes: 1

Views: 117

Answers (2)

metatoaster
metatoaster

Reputation: 18908

You had a typo. It's __lt__, not __it__, and you need to call the area() as a function unless you set that as a property.

Fixing all that...

>>> class Rectangle:
...     def __init__(self, x, y):
...        self.width = x
...        self.height = y
...     def area(self):
...        a = self.width * self.height
...        return a
...     def __lt__(self,second):
...        return self.area() < second.area()
... 
>>> Rectangle(1,3) > Rectangle(4,5)
False

Upvotes: 4

nerdwaller
nerdwaller

Reputation: 1863

Area is a method, you're using it as though it's a variable. Adding parens should fix it (and if you're trying to do less than, it should be __lt__):

def __lt__(self, second):
    return self.area() < second.area()

Upvotes: 0

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