CODEWITHSUNDEEP
c#xmllinq
JimDel
JimDel

Reputation: 4359

How can I check for a NullReferenceException in this C# LINQ to XML statement?

How can I check for a NullReferenceException in this C# LINQ to XML statement without wrapping the whole thing in a try/catch? If any of the properties are null, I would like it to still attempt to get the remaining data.

Thanks.

XElement doc = XElement.Load("test.xml");

var nodes =
   from node in doc.Elements("Customer")
   select new
   {
       Name = node.Element("FullName").Value,
       Zip = node.Element("ZipCode").Value,
       Active = node.Element("ActiveCustomer").Value,
   };

Upvotes: 1

Views: 100

Answers (4)

Ehsan Sajjad
Ehsan Sajjad

Reputation: 62488

you can use ternary operator to check for null.

do like this:

var nodes =
from node in doc.Elements("Customer")
select new
{
    Name = node.Element("FullName") !=null ? node.Element("FullName").Value : null,
    Zip = node.Element("ZipCode") !=null ? node.Element("ZipCode").Value : null,
    Active = node.Element("ActiveCustomer") !=null ? node.Element("ActiveCustomer").Value : null
};

Upvotes: 2

Selman Genç
Selman Genç

Reputation: 101691

Just use explicit cast. It will return null if the element wasn't found, won't cause an exception.

var nodes =
from node in doc.Elements("Customer")
select new
{
   Name = (string)node.Element("FullName"),
   Zip = (string)node.Element("ZipCode"),
   Active = (string)node.Element("ActiveCustomer"),
};

Upvotes: 6

Christos
Christos

Reputation: 53958

You could try this one:

select new
{
    Name = node.Element("FullName")!=null ? node.Element("FullName").Value : null,
    Zip = node.Element("ZipCode")!=null ? node.Element("ZipCode").Value : null,
    Active = node.Element("ActiveCustomer")!=null ? node.Element("ActiveCustomer").Value : null
};

The ? is the conditional operator. For further documentation about this, please have a look here.

Upvotes: 3

Cam Bruce
Cam Bruce

Reputation: 5689

Use the ternary operator.

Ternary Operator

XElement doc = XElement.Load("test.xml");

var nodes =
from node in doc.Elements("Customer")
select new 
{
  Name = node.Element("FullName") !=null ? node.Element("FullName").Value : null,
  Zip = node.Element("ZipCode") !=null ? node.Element("ZipCode").Value : null,
  Active = node.Element("ActiveCustomer") !=null ? node.Element("ActiveCustomer").Value : null
};

Upvotes: 3

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