CODEWITHSUNDEEP
java
Joao Victor
Joao Victor

Reputation: 1171

Working with cents and thousands in java

I have an input which can have a 13 long decimal number with cents and thousands separators. So i can have something like this:

13.213.232.132,13

The same field on my database table is configured to be a NUMBER(13,2) column (oracle)

How can i convert from 

13.213.232.132,13 to 13213232132,13

and Vice-Versa?

Upvotes: 3

Views: 372

Answers (4)

atmin
atmin

Reputation: 370

A very ugly approach, maybe it helps:

public static void main(final String[] args) {
    final String str = "12.345.678.912,13";
    final String improved = str.replaceAll("\\.", "").replaceAll(",", ".");
    System.out.println(improved);
    final double dbl = Double.parseDouble(improved);
    System.out.println("For database: " + dbl);
    // You may even pass a Locale to String::format
    final String str2 = String.format("%,f", dbl);
    System.out.println(str2);

    final String stringResult = str2.substring(0, str2.length() - 4);
    System.out.println(stringResult);
}

Upvotes: 0

Frakcool
Frakcool

Reputation: 11153

SOLUTION 1

You might want to use DecimalFormat

Here's an example on how to use it.

import java.util.*;
import java.text.*;
class NumberConverter {
    public static void main(String args[]) {
        double number = 12312312312.31;
        String pattern = "###.##";
        String pattern2 = "###,###.##";
        DecimalFormat myFormatter = new DecimalFormat(pattern);
        System.out.println(myFormatter.format(number));
        myFormatter = new DecimalFormat(pattern2);
        System.out.println(myFormatter.format(number));
    }
}

All you need to do with this example is replace , for . and viceversa. (I mean separators).

The actual output for my example is:

12312312312.31
12,312,312,312.31

SOLUTION 2

Here's another option on how to achieve it, code taken from @JonSkeet answer. Setting locale, but again assuming your number is a double.

import java.util.*;
import java.text.*;
class NumberConverter {
    public static void main(String args[]) {
        double number = 13213232132.13;
        NumberFormat f = NumberFormat.getInstance(Locale.GERMANY);
        ((DecimalFormat) f).applyPattern("##0,000.00");
        System.out.println(f.format(number));
    }
}

SOLUTION 3

If your input is a String then this could be another way of solving (Since it's a 13 length number that's why I use those limits).

import java.util.*;
import java.text.*;
import java.lang.StringBuilder;
class NumberConverter {
    public static void main(String args[]) {
        String number = "13.213.232.132,13";
        String number1;
        String number2;
        
        number1 = number.replace(".", "");
        
        int length;
        int length1;
        StringBuilder sb = new StringBuilder();
        
        sb.append(number1.charAt(0));
        sb.append(number1.charAt(1));
        sb.append(".");
        
        int counter = 0;
        for(int i = 2; i < 11; i++) {
            if(counter == 3) {
                sb.append(".");
                counter = 0;
            }
            sb.append(number1.charAt(i));
            counter++;
        }
        sb.append(",");
        sb.append(number1.charAt(12));
        sb.append(number1.charAt(13));
        
        number2 = sb.toString();
        
        System.out.println(number);
        System.out.println(number1);
        System.out.println(number2);
    }
}

SOLUTION 4

As @kaos said in his comment you can also do it by using DecimalFomatSymbols in this way:

import java.util.*;
import java.text.*;
import java.lang.StringBuilder;
class NumberConverter {
    public static void main(String args[]) {
        String formatString = "###,###.##";
        double number = 12312312312.31;
        DecimalFormatSymbols otherSymbols = new DecimalFormatSymbols(Locale.getDefault());
        otherSymbols.setDecimalSeparator(',');
        otherSymbols.setGroupingSeparator('.'); 
        DecimalFormat df = new DecimalFormat(formatString, otherSymbols);
        
        System.out.println(df.format(number));
    }
}

Any of these examples might help you in what you're trying to do.

Upvotes: 2

squallsv
squallsv

Reputation: 492

Use DecimalFormat:

DecimalFormat formatter = (DecimalFormat) DecimalFormat.getInstance(new Locale("pt", "br"));
    formatter.applyPattern("#0.##"); //i guess this is the pattern you need.

    System.out.println(formatter.format(new BigDecimal("13213232132.13")));

Upvotes: 1

arcy
arcy

Reputation: 13133

I'd use NumberFormat.parse() -- get an instance of NumberFormat to match your locale, create a string indicating the format expected, then parse the input with it.

Upvotes: 2

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