Reputation: 2394
I have a windows custom control with a picturebox
and a button
on it's default panel
. This windows custom control will be added to a windows form. There is another windows form called form2
. when the user double clicks on the custom control, it should load form2
. in designer when i double clicked the custom control on the form, it creates a load()
event for that custom control. But i need double click event, how this can be done?
here is the graphical view of what happens
Here is code in the control
[DefaultEvent("DoubleClick")]
public partial class cntrlImageLoader : UserControl
{
public cntrlImageLoader()
{
InitializeComponent();
}
private void btnBrowse_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.InitialDirectory = Environment.SpecialFolder.MyPictures.ToString();
if (ofd.ShowDialog() == DialogResult.OK)
{
pbImage.Image = Image.FromFile(ofd.FileName);
}
}
private void pbImage_Click(object sender, EventArgs e)
{
this.cntrlImageLoader_DoubleClick(pbImage, e);
}
private void cntrlImageLoader_Load(object sender, EventArgs e)
{
}
private void cntrlImageLoader_DoubleClick(object sender, EventArgs e)
{
}
}
Here is the calling code on form1
private void cntrImLdrFront_DoubleClick(object sender, EventArgs e)
{
//this.cntrImLdrFront.pbImage.DoubleClick += new EventHandler(pbImage_DoubleClick);
}
FrmImageViewer f; // this is form2
private void pbImage_DoubleClick(object sender, EventArgs e)
{
f= new FrmImageViewer();
f.MdiParent = this.MdiParent;
f.Show();
}
Upvotes: 2
Views: 296
Reputation: 6849
Assign the attribute [DefaultEvent("DoubleClick")]
at the class declaration.
[DefaultEvent("DoubleClick")]
public partial class MyControl : UserControl
{
}
This will creates event which you have set by default on double click of control at design time where you have placed your user control.
EDITED:
[DefaultEvent("LoadPicture")]
public partial class cntrlImageLoader : UserControl
{
public delegate void LoadPictureEventHandler(object sender, LoadPictureEventArgs e);
public event LoadPictureEventHandler LoadPicture;
private void pbImage_DoubleClick(object sender, EventArgs e)
{
if (LoadPicture != null)
{
LoadPictureEventArgs ev = new LoadPictureEventArgs();
LoadPicture(this, ev);
if (ev.Picture != null)
{
pbImage.Image = ev.Picture;
}
}
}
}
Create another class and give that class name to LoadPictureEventArgs
public class LoadPictureEventArgs : EventArgs
{
public Image Picture {get; set;}
public LoadPictureEventArgs(Image _picture)
{
Picture = _picture
}
public LoadPictureEventArgs()
: base()
{
}
}
HOW TO USE IT?
//FORM1
private void cntrImLdrFron_LoadPicture(object sender, LoadPictureEventArgs e)
{
Image img = null;
//LOAD YOUR IMAGE HERE
e.Picture = img;
}
Upvotes: 1