CODEWITHSUNDEEP
javafileurl
bLaXjack
bLaXjack

Reputation: 870

How to know whether a string path is Web URL or a File based

I have a text field to acquire location information (String type) from User. It could be file directory based (e.g. C:\directory) or Web url (e.g. http://localhost:8008/resouces). The system will read some predetermined metadata file from the location.

Given the input string, how can I detect the nature of the path location whether it is a file based or Web URL effectively.

So far I have tried.

URL url = new URL(location); // will get MalformedURLException if it is a file based.
url.getProtocol().equalsIgnoreCase("http");

File file = new File(location); // will not hit exception if it is a url.
file.exist(); // return false if it is a url.

I am still struggling to find a best way to tackle both scenarios. :-(

Basically I would not prefer to explicitly check the path using the prefix such as http:// or https://

Is there an elegant and proper way of doing this?

Upvotes: 10

Views: 9766

Answers (4)

Hypersoft Systems
Hypersoft Systems

Reputation: 518

public boolean urlIsFile(String input) {
    if (input.startsWith("file:")) return true;
    try { return new File(input).exists(); } catch (Exception e) {return false;}
}

This is the best method because it is hassle free, and will always return true if you have a file reference. For instance, other solutions don't and cannot cover the plethora of protocol schemes available such as ftp, sftp, scp, or any future protocol implementations. So this one is the one for all uses and purposes; with the caveat of the file must exist, if it doesn't begin with the file protocol.

if you look at the logic of the function by it's name, you should understand that, returning false for a non existent direct path lookup is not a bug, that is the fact.

Upvotes: 0

John Chesshir
John Chesshir

Reputation: 640

If you're open to the use of a try/catch scenario being "elegant", here is a way that is more specific:

try {
    processURL(new URL(location));
}
catch (MalformedURLException ex){
    File file = new File(location);
    if (file.exists()) {
        processFile(file);
    }
    else {
        throw new PersonalException("Can't find the file");
    }
}

This way, you're getting the automatic URL syntax checking and, that failing, the check for file existence.

Upvotes: 3

user1708042
user1708042

Reputation: 1863

you can try:

static public boolean isValidURL(String urlStr) {
    try {
      URI uri = new URI(urlStr);
      return uri.getScheme().equals("http") || uri.getScheme().equals("https");
    }
    catch (Exception e) {
        return false;
    }
}

note that this will return false for any other reason that invalidates the url, ofor a non http/https url: a malformed url is not necessarily an actual file name, and a good file name can be referring to a non exisiting one, so use it in conjunction with you file existence check.

Upvotes: 1

icza
icza

Reputation: 417702

You can check if the location starts with http:// or https://:

String s = location.trim().toLowerCase();
boolean isWeb = s.startsWith("http://") || s.startsWith("https://");

Or you can use the URI class instead of URL, URI does not throw MalformedURLException like the URL class:

URI u = new URI(location);
boolean isWeb = "http".equalsIgnoreCase(u.getScheme())
    || "https".equalsIgnoreCase(u.getScheme())

Although new URI() may also throw URISyntaxException if you use backslash in location for example. Best way would be to either use prefix check (my first suggestion) or create a URL and catch MalformedURLException which if thrown you'll know it cannot be a valid web url.

Upvotes: 7

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