CODEWITHSUNDEEP
c#graphing
George Johnston
George Johnston

Reputation: 32278

Find coordinate by angle

I am developing in application in XNA which draws random paths. Unfortunately, I'm out of touch with graphing, so I'm a bit stuck. My application needs to do the following:

  1. Pick a random angle from my origin (0,0), which is simple.
  2. Draw a circle in relation to that origin, 16px away (or any distance I specify), at the angle found above.

(Excuse my horrible photoshoping)

alt text http://www.refuctored.com/coor.png

The second circle at (16,16) would represent a 45 degree angle 16 pixels away from my origin.

I would like to have a method in which I pass in my distance and angle that returns a point to graph at. i.e.

private Point GetCoordinate(float angle, int distance)
{
   // Do something.
   return new Point(x,y);
}

I know this is simple, but agian, I'm pretty out of touch with graphing. Any help?

Thanks, George

Upvotes: 2

Views: 10360

Answers (4)

Jakob Borg
Jakob Borg

Reputation: 24505

private Point GetCoordinate(float angle, int distance)
{
  float x = cos(angle) * distance;
  float y = sin(angle) * distance;
  return new Point(x, y);
}

Note that the trigonometric functions probably take radians. If your angle is in degrees, divide by 180/Pi.

Upvotes: 1

Jaxidian
Jaxidian

Reputation: 13511

Learn the Pythagorean Theorem. Then this thread should have more specific details for you.

Upvotes: 0

charlieb
charlieb

Reputation: 597

in general:

x = d * cos(theta)
y = d * sin(theta)

Where d is the distance from the origin and theta is the angle.

Upvotes: 0

Thomas
Thomas

Reputation: 182038

If the angle is in degrees, first do:

angle *= Math.PI / 180;

Then:

return new Point(distance * Math.Cos(angle), distance * Math.Sin(angle));

By the way, the point at (16, 16) is not 16 pixels away from the origin, but sqrt(16^2 + 16^2) = sqrt(512) =~ 22.63 pixels.

Upvotes: 5

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