Reputation: 473
unknown host exception coming while connecting to ejabberd server.
public static final String HOST = "http://54.254.220.129:5280/admin";
public static final int PORT = 5222;
public static final String SERVICE = "localhost";
public static final String USERNAME = "admin@localhost";
public static final String PASSWORD = "########";
ConnectionConfiguration connConfig = new ConnectionConfiguration(HOST, PORT, SERVICE);
XMPPConnection connection = new XMPPConnection(connConfig);
enter code here
try {
connection.connect();
Log.i("XMPPChatDemoActivity",
"[SettingsDialog] Connected to "
+ connection.getHost());
} catch (XMPPException ex) {
Log.e("XMPPChatDemoActivity",
"[SettingsDialog] Failed to connect to "
+ connection.getHost());
Log.e("XMPPChatDemoActivity", ex.toString());
setConnection(null);
}
any answer will be appreciable ! thanks
Upvotes: 1
Views: 1737
Reputation: 344
In your HOST string you already wrote the port number. So i think you need to write only ip address without port and admin like http://54.254.220.129
.
- After that try to connect. And try to login.
Try this;
public static final String HOST = "http://54.254.220.129";
public static final int PORT = 5222;
public static final String SERVICE = "localhost";
public static final String USERNAME = "admin@localhost";
public static final String PASSWORD = "########";
ConnectionConfiguration connConfig = new ConnectionConfiguration(HOST, PORT, SERVICE);
XMPPConnection connection = new XMPPConnection(connConfig);
connection.connect();
connection.login(USERNAME, PASSWORD);
Upvotes: 3
Reputation: 59671
Traditional XMPP doesn't use HTTP
You can't connect to http://54.254.220.129:5280/admin
(this is for browsers!)
You need to use just the IP address
public static final String HOST = "54.254.220.129";
Upvotes: 7