CODEWITHSUNDEEP
javajuniteasymock
lapots
lapots

Reputation: 13395

Unexpected method call when run junit easymock test

I want to test this method and its conditions.

public String getType(String body) {
    String type = getTypeCode(body, 1); //this
    if (null == type) {
        type = getTypeCode(body, 2); //this
    }
    return type;
}

So I've written a test

@Test
public void testTypeOldToNew() {
    Parser parser = createMock(Parser.class);
    expect(parser.getTypeCode(BODY_2, 1)).andReturn(null);
    expect(parser.getTypeCode(BODY_2, 2)).andReturn(CODE_TWO_MESSAGE);
    replay(parser);
    parser.getType(BODY_2);
    verify(parser);
}

But when I run it I've got an error

java.lang.AssertionError: 
  Unexpected method call Parser.getype("value"):
    Parser.getTypeCode("value", 1): expected: 1, actual: 0
    Parser.getTypeCode("value", 2): expected: 1, actual: 0

Why? What's the problem?

Upvotes: 0

Views: 6250

Answers (1)

Mark Rotteveel
Mark Rotteveel

Reputation: 108970

You can't mock the class you are testing. You are calling parser.getType(BODY_2); on the mock. And as you haven't defined anything for that method, nothing happens (and defining what should happen doesn't make sense, because then you would be testing the mocking framework).

You need to mock interactions of this class with other classes (or better: interfaces).

Upvotes: 3

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