Reputation: 34200
In the following model:
class header(models.Model):
title = models.CharField(max_length = 255)
created_by = models.CharField(max_length = 255)
def __unicode__(self):
return self.id()
class criteria(models.Model):
details = models.CharField(max_length = 255)
headerid = models.ForeignKey(header)
def __unicode__(self):
return self.id()
class options(models.Model):
opt_details = models.CharField(max_length = 255)
headerid = models.ForeignKey(header)
def __unicode__(self):
return self.id()
If there is a row in the database for table header as
Id=1, title=value-mart , createdby=CEO
How do I query criteria and options tables to get all the values related to header table id=1
Also can some one please suggest a good link for queries examples.
Upvotes: 11
Views: 30510
Reputation: 44326
Sounds like you are looking for Following relationships "backward".
You can get the header object you want to filter by, and use something like
obj = Header.objects.get(title="value-mart", "createdby=CEO")
obj.criteria_set.all()
Look at the documentation for more detailed info
Upvotes: 5
Reputation: 600059
Ironfroggy is right, but there is another more obvious way to get the relevant options
and criteria
objects. Django automatically creates a 'reverse relation' for every foreign key pointing at a model, and that is usually the name of the related model plus _set
. So:
mycriteria.options_set.all()
mycriteria.header_set.all()
will give you all the options
and header
objects related to a criteria
object mycriteria
.
Also, a note on style: as ironfroggy pointed out, you shouldn't use id
in the foreign key fields, but also you should use Capitalised style for your model classes, so you can see a difference between the class Criteria
and a particular instance criteria
.
In terms of links, the Django documentation is excellent and explains all of this.
Upvotes: 22
Reputation: 13722
I would suggest trying to us a coding style and naming convention that is more like you see in the Django documentation for Models. Something more like this:
class Header(models.Model):
...
class Criteria(models.Model):
details = model.CharField(max_length=255)
header = models.ForeignKey(Header)
And then query them as needed:
# find Criteria for a given header
value_mart = Header.objects.get(id=1)
# ... via an instance of Header.
value_mart.criteria_set.all()
# ... or with a filter().
Criteria.objects.filter(header=value_mart)
Criteria.objects.filter(header_id=1)
The documentation for many-to-one relationships also references a usage example.
Upvotes: 5
Reputation: 8125
First of all, don't use id
in the names, because it is confusing. That field isn't the ID, it is the object itself. (If you have a field ref
it automatically creates a field ref_id
)
options.objects.filter(header=a_header)
You query it like any value, where some header instance is the value you are filtering on.
Upvotes: 9