CODEWITHSUNDEEP
python
tudoricc
tudoricc

Reputation: 729

Issue when converting a tuple to a string

I don't know a lot about python so please be patient with me:

Let's say we have a tuple that has this form:

 locations = [('John' , 32 , 21) , ('Michael' , 23 , 12)]

How can I concatenate them to a string that looks like

"John 32 21

Michael 23 12"

I tried doing this:

str1 = '\n'.join( ' '.join(elem[0] elem [1] elem[2]) for elem in locations)

But I get an error at the elem[0],[1],[2] saying Invalid Syntax

Any ideas on how I can fix this?

Upvotes: 1

Views: 78

Answers (4)

user1023380
user1023380

Reputation: 51

You can do this:

>>>['%s %s %s' %i for i in locations]
['John 32 21', 'Michael 23 12']

with line feed:

>>>print '\n'.join(['%s %s %s' %i for i in locations])
John 32 21 
Michael 23 12

Upvotes: 1

idwaker
idwaker

Reputation: 416

[edit] Or try this

>>> '\n'.join([' '.join(map(lambda c: str(c), elem)) for elem in locations])
>>> 'John 32 21\nMichael 23 12'

map(lambda c: str(c), elem) takes every element from locations ie from ('John' , 32 , 21) 'John', 32 and 21 and converts into string and returns ['John', '32', '21'] which is then join using ' ' and finally by '\n'

Updated:

>>> '\n'.join([' '.join(map(str, elem)) for elem in locations])

learned, thanks

Upvotes: 2

Padraic Cunningham
Padraic Cunningham

Reputation: 180401

Your own code need to have each elem separated by a comma and the three elements wrapped inside a container:

 ' '.join(elem[0] elem [1] elem[2]) # invalid syntax, join takes a single iterable

'\n'.join( ' '.join((str(elem[0]), str(elem[1]) ,str(elem[2]))) for elem in locations)

You can use unpacking and map to do the same:

'\n'.join( ' '.join(map(str,(a,b,c))) for a,b,c in locations)

Or simply:

 '\n'.join( ' '.join(map(str,elem)) for elem in locations)

Upvotes: 1

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 798606

>>> '\n'.join(' '.join(str(y) for y in x) for x in locations)
'John 32 21\nMichael 23 12'

Upvotes: 5

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