CODEWITHSUNDEEP
csh
dromodel
dromodel

Reputation: 10203

How can I avoid a "no match" error in this C shell script?

Consider the following C shell script:

set MYVAR = "a='str.*' -p -10"
set output = `echo "$MYVAR" | sed 's/-p -[0-9]\+/-p -100/g'`
echo "$output"

When sourced from the shell, I get the error echo: no match. What changes can I make to the script to avoid the error? I tried adding ":q" and using a Perl one liner but haven't found an elegant solution.

Upvotes: 1

Views: 4959

Answers (1)

Susan Eraly
Susan Eraly

Reputation: 339

This is tricky because you have both ".*" {which would glob for files} and a single quote in MYVAR {which means you can't use the ' to say interpret literally} The best I can think of here is to replace the double quote in MYVAR with single quotes in which case everything should work. Your sed line doesn't work. But that is not the problem. I replaced the sed to mimic what I think you are trying to do.

So:

- set MYVAR = 'a="str.*" -p -10'
- echo $MYVAR
  echo: No match. #as expected because you need to put it in double quotes
- echo "$MYVAR"
  a="str.*" -p -10
- set output = `echo "$MYVAR" | sed 's/-p -10/-p -100/g'`
- echo $output
  echo: No match. #Reason same as before
- echo "$output"
  a="str.*" -p -100

Upvotes: 2

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