CODEWITHSUNDEEP
iphoneurliphone-sdk-3.0uiapplication
agentfll
agentfll

Reputation: 858

UIApplication openUrl not working with formatted NSString

I have the following code to open google maps:

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];

But it doesn't work and there is no error. It just doesn't open.

Upvotes: 18

Views: 12813

Answers (2)

Biranchi
Biranchi

Reputation: 16327

Need to escape the urlString , else [NSURL URLWithString:urlString] will return nill. 

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding] ]];

Upvotes: 5

user121301
user121301

Reputation:

URLWithString requires a percent-escaped string. Your sample url contains spaces which results in a nil NSURL being created. Additionally, the addressString may also contain characters that need to be escaped. Try percent-escaping the url string first:

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
NSString *escaped = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:escaped]];

Upvotes: 44

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