Reputation: 344
I have the following code segment to run a bat file:
String workingDir = System.getProperty("user.dir");
ProcessBuilder pb = new ProcessBuilder("cmd", "/c",
"\"" + workingDir + File.separator + "midl.bat\"");
Process ddsBuildProc = pb.start();
ddsBuildProc.waitFor();
The workingDir includes spaces in the path. Eventhough I use quotes to enclose the workingDir+fileName string, the shell still splits the workingDir and doesn't run the bat file. If a try and copy-paste-execute the bat file path string in the Windows command window manually, it works as expected. What can be the problem here?
Also, please do not close this question as duplicate because I tried all the solutions in the other questions with no success.
Upvotes: 4
Views: 4285
Reputation: 347334
user.dir
is your programs current executing context...so it actually makes no sense to include it, you could just use midl.bat
by itself (assuming the command exists within the current execution context)I wrote a really simple batch file...
@echo off
dir
Which I put in my "C:\Program Files" directory, as I need a path with spaces and used....
import java.io.File;
import java.io.IOException;
import java.io.InputStream;
import java.util.logging.Level;
import java.util.logging.Logger;
public class RunBatch {
public static void main(String[] args) {
ProcessBuilder pb = new ProcessBuilder(
"cmd", "/c", "listme.bat"
);
pb.directory(new File("C:/Program Files"));
pb.redirectError();
try {
Process process = pb.start();
InputStreamConsumer.consume(process.getInputStream());
System.out.println("Exited with " + process.waitFor());
} catch (IOException | InterruptedException ex) {
ex.printStackTrace();
}
}
public static class InputStreamConsumer implements Runnable {
private InputStream is;
public InputStreamConsumer(InputStream is) {
this.is = is;
}
public static void consume(InputStream inputStream) {
new Thread(new InputStreamConsumer(inputStream)).start();
}
@Override
public void run() {
int in = -1;
try {
while ((in = is.read()) != -1) {
System.out.print((char) in);
}
} catch (IOException exp) {
exp.printStackTrace();
}
}
}
}
To run it without any issues...
Upvotes: 4