CODEWITHSUNDEEP
javascriptjquery
ntgCleaner
ntgCleaner

Reputation: 5985

javascript how to return a number from an object variable

So, I have a large object called con in that object, I have many variables, numbered sort of like an excel sheet, b19, b20, b21, etc.

I am trying to return a value from each one, but when I do a console log, It logs the entire function, not just the return.

Here's how the object is set up:

var con = {
    b13: function(){
        return 12600.535*Math.sqrt((con.b14+459.4)/459.4)
    },
    b14: function(){
        return 20;
    }
}

$(document).ready(function(){
    console.log(con.b13);
});

This outputs this into the console:

function(){
    return 12600.535*Math.sqrt((con.b14+459.4)/459.4)
}

So how do I format this so that it outputs the actual number in the equation?

Upvotes: 0

Views: 49

Answers (5)

user3886234
user3886234

Reputation:

The problem is that your object's properties are functions, but you are trying to call them as if they were values.

For example, if you wanted correctly log con.b13's value to the console, you would need to change the command to:

console.log(con.b13());

What this does is get what con.b13 returns rather than what it is.

If you don't want to go through the hassle of adding a () next to every reference, you can modify the object and define getters like this:

var con = {
    get b13() {
        return 12600.535 * Math.sqrt((con.b14 + 459.4) / 459.4)
    },

    get b14() {
        return 20;
    }
}

If you define the object like this, your original command console.log(con.b13) will work as intended.

Upvotes: 0

plalx
plalx

Reputation: 43718

You can simply use es5 getters/setters.

var con = {
    get b13() {
        return 12600.535*Math.sqrt((con.b14+459.4)/459.4);
    },
    get b14() {
        return 20;
    }
};

Upvotes: 0

Gary Storey
Gary Storey

Reputation: 1814

Try console.log(con.b13()); . You are logging the function definition not executing it.

Upvotes: 2

cdhowie
cdhowie

Reputation: 169018

You need to make b13 and b14 properties with a getter function:

var con = {};

Object.defineProperty(con, "b13", {
    get: function() {
        return 12600.535*Math.sqrt((con.b14+459.4)/459.4);
    }
});

Object.defineProperty(con, "b14", {
    get: function() { return 20; }
});

This will cause con.b13 and con.b14 to call the given functions, returning whatever the functions return.

Upvotes: 2

kirinthos
kirinthos

Reputation: 452

you don't define the properties as functions...

var con = {
  b13: 239487,
  b12: 923748
};

edit: if some properties need to be functions you have to call them e.g. con.b14(), not con.b14 as a property

Upvotes: 1

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