zelinka
zelinka

Reputation: 3413

downloading an excel file from the web in python

I have the following web address:

dls = "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls"

I tried to download the file:

urllib2.urlopen(dls, "test.xls")

This made a file called "test.xls" but this is clearly an html file. If I opened the html file in firefox it opened an excel file, but if I opened the file in excel it was definitely not the excel file I was looking for.

If I have a web address like the one above, how do I make python download the excel file as an excel file?

Upvotes: 22

Views: 116403

Answers (4)

mnjeremiah
mnjeremiah

Reputation: 281

This would save the excel file in the same folder that the script was ran from.

import urllib
dls = "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls"
urllib.request.urlretrieve(dls, "test.xls")  # For Python 3
# urllib.urlretrieve(dls, "test.xls")  # For Python 2

Upvotes: 12

Fedalto
Fedalto

Reputation: 1567

I suggest using requests:

import requests
dls = "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls"
resp = requests.get(dls)

output = open('test.xls', 'wb')
output.write(resp.content)
output.close()

To get requests installed:

pip install requests

Upvotes: 43

Aaron Hall
Aaron Hall

Reputation: 395773

To add on to Fedalto's requests suggestion (+1), but make it more Pythonic with a context manager:

import requests
dls = "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls"
resp = requests.get(dls)
with open('test.xls', 'wb') as output:
    output.write(resp.content)

Upvotes: 21

BKay
BKay

Reputation: 1457

Two issues, one with the code (below), the other that the URL is bad. A (modern) web browser will automatically correct "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls" to "http://www.muellerindustries.com/uploads/pdf/UW%20SPD0114.xls" but Python doesn't.

This code works for me on python 3.x

import urllib
outfilename = "test.xls"
url_of_file = "http://www.muellerindustries.com/uploads/pdf/UW%20SPD0114.xls"
urllib.request.urlretrieve(url_of_file, outfilename) 

Which gets me the file.

Upvotes: 5

Related Questions