Reputation: 8086
I'm not sure how to do this without hacking something completely ridiculous and experience has thought me that someone can probably suggest 1 or 2 lines of code that will do exactly what I want. I'm not sure where to look, so here's my question:
Say I want to display a chart of month to date daily signups. So I need an efficient sql statement.
I want this to return a hash like this:
{ "2014-08-01"=>83, "2014-08-02"=>67, "2014-08-03"=>109, ... }
Which I can then use to generate a wicked cool chart! =)
So I have no idea how to write this query. Can someone help me please? Thanks...
Here is my "hacked" attempt:
h = User.group("created_at").count
(0.7ms) SELECT COUNT(*) AS count_all, created_at AS created_at FROM "users" GROUP BY created_at
#=> {nil=>5, 2014-07-27 17:19:41 UTC=>1, 2014-07-19 00:23:54 UTC=>1, 2014-08-21 18:02:58 UTC=>1, 2014-08-21 18:39:31 UTC=>1, 2014-08-21 17:32:48 UTC=>1, 2014-08-21 17:21:46 UTC=>1, 2014-08-21 18:36:21 UTC=>1, 2014-08-21 16:29:37 UTC=>1, 2014-08-21 18:54:34 UTC=>1, 2014-08-21 17:56:24 UTC=>1, 2014-08-21 18:33:20 UTC=>1, 2014-08-21 16:27:17 UTC=>1, 2014-08-21 19:16:11 UTC=>1, 2014-08-21 18:41:14 UTC=>1, 2014-08-21 18:14:12 UTC=>1, 2014-08-21 18:30:46 UTC=>1, 2014-08-21 18:28:04 UTC=>1}
dates = h.keys.compact.map {|j| j.to_s.match(/\d*-\d*-\d*/)[0] }
#=> ["2014-07-27", "2014-07-19", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21", "2014-08-21"]
signUpHash = Hash.new 0
#=> {}
dates.map do |date|
signUpHash[date] += 1
end
#=> [1, 1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
signUpHash
#=> {"2014-07-27"=>1, "2014-07-19"=>1, "2014-08-21"=>15}
signUpHash.sort.to_h
#=> {"2014-07-19"=>1, "2014-07-27"=>1, "2014-08-21"=>15}
So though my way works (somewhat because it doesn't actually take into account month to date which would require more hacking) so... (I know there is a better, more efficient, more legible, more reliable, preferred, recommended, ideal ... (you get the point) ... way to do this. Please advise. Thanks! =)
Upvotes: 0
Views: 277
Reputation: 324911
If writing SQL directly, you'd use date_trunc
.
You haven't shown table definitions or sample data so I can't really test it or write a full query, but the general principle is:
SELECT date_trunc('month', created_at), count(created_at)
FROM mytable
GROUP BY date_trunc('month', created_at)
ORDER BY 1;
to produce a resultset of first-day-of-month to count pairs that're then trivially consumed and aggregated into a hash in the client. You could build the hash in the SQL query, but there's not really any benefit to doing so.
Note that an index on created_at
cannot be used for this query. If you want to limit it to certain dates, do so with a WHERE
clause on created_at
, not using the resulting date_trunc
'd values.
If you run this a lot and need it to be fast, and don't mind the additional write overhead of an extra index, you can create a composite index on the month:
create index blahwhateverindexname on mytablename( (date_trunc('month', created_at) );
Upvotes: 1