CODEWITHSUNDEEP
jquerytabs
sam
sam

Reputation: 345

Open each link from array in new tab

I have an array like

myArray = ["http://www.google.co.uk", "http://www.ebay.co.uk"]

and I want to open them all in a new tab. The code I am using just puts all the urls together and tried to open it in one.

Any help greatly appreciated

  $.each(
                myArray,
                function( intIndex, objValue ){

                    window.open(myArray);
                }
                );
  })

Upvotes: 0

Views: 2379

Answers (2)

Jatinder Kumar
Jatinder Kumar

Reputation: 513

The correct code is:

var myArray = ["http://www.google.co.uk", "http://www.ebay.co.uk"];
$(document).ready(function() {
$.each(
    myArray,
    function( intIndex, objValue ){
        window.open(objValue);
    });
});

You used the array variable in window.open, thats why it was joining the urls.

Upvotes: 0

Ehsan Sajjad
Ehsan Sajjad

Reputation: 62488

you are passing whole myArray to window.open(), you have to pass each item value.

change:

window.open(myArray);

to:

window.open(objValue);

Like this:

var myArray = ["http://www.google.co.uk", "http://www.ebay.co.uk"];

$.each(myArray,function (intIndex, objValue) {

    window.open(objValue);
});

FIDDLE:

http://jsfiddle.net/ehsansajjad465/4jj9x3z5/

Upvotes: 2

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