CODEWITHSUNDEEP
springspring-mvc
Alex
Alex

Reputation: 883

Parse JSON request without creating a class

In a Spring MVC controller method, I have a JSON input (request body) with just one field: {"version":3}. I can get this value like this:

@RequestMapping
public void myMethod(@RequestBody MyJsonRequest myJsonRequest) {

    int version = myJsonRequest.version;

    //...
}

But I have to create MyJsonRequest class with a version field. How can I get the version value without creating a new class?

Upvotes: 0

Views: 1852

Answers (3)

jny
jny

Reputation: 8057

You can try using a map:

public void myMethod(@RequestBody Map<String, Integer> myJsonRequest) {

    int version = myJsonRequest.get("version");

    //...
}

Upvotes: 3

Kerem YILDIZ
Kerem YILDIZ

Reputation: 70

Try the code below, it maps your json object to a primitive int variable: 

@RequestMapping(value="/yourMapping", method=RequestMethod.POST, consumes=MediaType.APPLICATION_JSON)
public void myMethod (@RequestBody int version) {

    //do something with your int variable version
}

Upvotes: 0

Ghanshyam Katriya
Ghanshyam Katriya

Reputation: 1081

You can parse JSON data and then you can directly access to value of JSON response.

Consider data as myJsonRequest :

 var version=0;
 var jsonval = $.parseJSON(data);
 // you can use directly value of json data like 
 version = data.version;

 // If you returned an array in json response, then you can use $.each method and store value into single array, like this

 $.each(portals_array,function(i,v){
        version[] = v.version;

 });

alert(version);
};

It's working perfectly in my code. Check it out.

Upvotes: 0

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