CODEWITHSUNDEEP
makefile
Atticus Sterman
Atticus Sterman

Reputation: 31

getting "*** missing separator. Stop." from makefile, already checked for tabs

Here is the makefile, the error is coming from line 5 ifeq($(PROD),all)

APP=all
LOC=en_US

html: loc
ifeq($(APP),all)
    @for app in apps/*; do echo "Building $app"; grunt --prod $app --loc $(LOC); done
else
    @grunt --prod $(APP) --loc $(LOC)
endif

loc:
ifeq($(LOC),en_US)
    @echo "Building $(LOC)"
else ifeq($(LOC),zh_CN)
    @echo "Building $(LOC)"
else
    @echo "Invalid LOC $(LOC)" && exit 1;
endif

From what I can tell from other stackexchange answers, this issue usually occurs when there are missing tabs, but I have checked that there are tabs for all of the sh code that needs running

Upvotes: 1

Views: 327

Answers (1)

Atticus Sterman
Atticus Sterman

Reputation: 31

Found it, there have to be spaces after ifeq statements.

html: loc
ifeq ($APP,all)

Upvotes: 2

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