Reputation: 46158
This table is used to store sessions (events):
CREATE TABLE session (
id int(11) NOT NULL AUTO_INCREMENT
, start_date date
, end_date date
);
INSERT INTO session
(start_date, end_date)
VALUES
("2010-01-01", "2010-01-10")
, ("2010-01-20", "2010-01-30")
, ("2010-02-01", "2010-02-15")
;
We don't want to have conflict between ranges.
Let's say we need to insert a new session from 2010-01-05 to 2010-01-25.
We would like to know the conflicting session(s).
Here is my query:
SELECT *
FROM session
WHERE "2010-01-05" BETWEEN start_date AND end_date
OR "2010-01-25" BETWEEN start_date AND end_date
OR "2010-01-05" >= start_date AND "2010-01-25" <= end_date
;
Here is the result:
+----+------------+------------+
| id | start_date | end_date |
+----+------------+------------+
| 1 | 2010-01-01 | 2010-01-10 |
| 2 | 2010-01-20 | 2010-01-30 |
+----+------------+------------+
Is there a better way to get that?
Upvotes: 98
Views: 61519
Reputation: 1396
Recently I was struggling to perform operations with date. The following SQL query solved the issue to filter rows with multiple criteria related to date:
SELECT * FROM duty_register WHERE employee = '2' AND (
(
duty_start_date BETWEEN start_date AND end_date
OR
duty_end_date BETWEEN start_date AND end_date
)
OR
(
start_date BETWEEN duty_start_date AND duty_end_date
OR
end_date BETWEEN duty_start_date AND duty_end_date)
);
PS: This helped me find the entries with overlapping date ranges however may not be a good approach as it may be memory consuming.
Upvotes: -1
Reputation: 333
Mackraken's answer above is better from a performance perspective as it doesn't require several OR's in order to evaluate if two dates overlap. Nice solution!
However I found that in MySQL you need to use DATEDIFF instead of the minus operator -
SELECT o.orderStart, o.orderEnd, s.startDate, s.endDate
, GREATEST(LEAST(orderEnd, endDate) - GREATEST(orderStart, startDate), 0)>0 as overlaps
, DATEDIFF(LEAST(orderEnd, endDate), GREATEST(orderStart, startDate)) as overlap_length
FROM orders o
JOIN dates s USING (customerId)
WHERE 1
AND DATEDIFF(LEAST(orderEnd, endDate),GREATEST(orderStart, startDate)) > 0;
Upvotes: 0
Reputation: 1
You can cover all date overlapping cases even when to-date in database can possibly be null as follows:
SELECT * FROM `tableName` t
WHERE t.`startDate` <= $toDate
AND (t.`endDate` IS NULL OR t.`endDate` >= $startDate);
This will return all records that overlaps with the new start/end dates in anyway.
Upvotes: 0
Reputation: 515
Given two intervals like (s1, e1) and (s2, e2) with s1<e1 and s2<e2
You can calculate overlapping like this:
SELECT
s1, e1, s2, e2,
ABS(e1-s1) as len1,
ABS(e2-s2) as len2,
GREATEST(LEAST(e1, e2) - GREATEST(s1, s2), 0)>0 as overlaps,
GREATEST(LEAST(e1, e2) - GREATEST(s1, s2), 0) as overlap_length
FROM test_intervals
Will also work if one interval is within the other one.
Upvotes: 5
Reputation: 754
I had faced the similar problem. My problem was to stop booking between a range of blocked dates. For example booking is blocked for a property between 2nd may to 7th may. I needed to find any kind of overlapping date to detect and stop the booking. My solution is similar to LordJavac.
SELECT * FROM ib_master_blocked_dates WHERE venue_id=$venue_id AND
(
(mbd_from_date BETWEEN '$from_date' AND '$to_date')
OR
(mbd_to_date BETWEEN '$from_date' AND '$to_date')
OR
('$from_date' BETWEEN mbd_from_date AND mbd_to_date)
OR
('$to_date' BETWEEN mbd_from_date AND mbd_to_date)
)
*mbd=master_blocked_dates
Let me know if it doesn't work.
Upvotes: 4
Reputation: 3428
SELECT * FROM tbl WHERE
existing_start BETWEEN $newStart AND $newEnd OR
existing_end BETWEEN $newStart AND $newEnd OR
$newStart BETWEEN existing_start AND existing_end
if (!empty($result))
throw new Exception('We have overlapping')
These 3 lines of sql clauses cover the 4 cases of overlapping required.
Upvotes: 40
Reputation: 75704
I had such a query with a calendar application I once wrote. I think I used something like this:
... WHERE new_start < existing_end
AND new_end > existing_start;
UPDATE This should definitely work ((ns, ne, es, ee) = (new_start, new_end, existing_start, existing_end)):
Here is a fiddle
Upvotes: 185
Reputation: 2027
Lamy's answer is good, but you can optimize it a little more.
SELECT * FROM tbl WHERE
existing_start BETWEEN $newSTart AND $newEnd OR
$newStart BETWEEN existing_start AND existing_end
This will catch all four scenarios where the ranges overlap and exclude the two where they don't.
Upvotes: 22