CODEWITHSUNDEEP
pythoneventsevent-handlingwxpythonsignals
Ram Rachum
Ram Rachum

Reputation: 88508

wxPython: Sending a signal to several widgets

I am not even sure how to ask this question. I want something that is like the wxPython event system, but a bit different. I'll try to explain.

When there is a certain change in my program (a "tree change", never mind what that is,) I want to send a signal to all the widgets in my program, notifying them that a "tree change" has occurred, and they should change their display in response.

How do I do this? It sounds a little bit like wxPython events, but not really, since events don't spread to all widgets, as far as I know.

What would be a good way to do this?

Upvotes: 1

Views: 928

Answers (2)

Anurag Uniyal
Anurag Uniyal

Reputation: 88727

You can write your own publish-subscribe mechanism which can be as simple as this:

def register(self, callback):
    self.callbacks.append(callback)

def emit(self, eventName):
    for callback in self.callbacks:
         callback(eventName)

Anybody interested in listening to event registers a function with central registry and then you can emit a event to interested parties, you can improve it further by having to register for a specific event, having multiple registrars, unregister, error checking etc

Alternatively you can use wxPython's wx.lib.pubsub module or other python libraries like PyPubsub , PyDispatcher

Upvotes: 6

Moayyad Yaghi
Moayyad Yaghi

Reputation: 3722

check out the observer design pattern. you need to implement the widgets as an observers . and the signal sender as the subject. so whenever it the subject sends a signal, all the observers will be notified.

check this out for more info about observers

Upvotes: 0

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