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pythonif-statement
Jansen Lopez
Jansen Lopez

Reputation: 41

If and elif in Python for good programming practices

Hello there I'm currently trying to get a good grasp of the if, elif, else structure in Python. I'm trying some weird combinations in python having a test program to know the output in this if, if, elif, elif, else code. However I'm getting weird results such as this

input = raw_input('Please enter the required digit: ')
intput = int(input)

if intput == 0:
    print 'if1'

if intput == 1:
    print 'if2'
elif intput == 0:
    print 'elif1'
elif intput == 1:
    print 'elif2'
else:
    print 'else'

if I in put 1 it will print "if2", I thought that it will also print "elif2" and other shenanigans when I try to change the "intput == n" code. So my question is do I have to stick to the if,elif, elif, .... n * elifs, else method which seems to me working alright than working with the wacky if,if.... n * ifs, elif, elif, ...n* elifs, else.

Thanks

Upvotes: 1

Views: 1383

Answers (2)

hackrole
hackrole

Reputation: 121

this may be more clear to understand:

if input == 0:
    print "if1"

switch(input):
    case 1:
        print "if2"
        break
    case 0:
        print "elif1"
        break
    case 1:
        print "elif2"
        break
    default:
        print "else"
        break

of course, the code does not work.

Upvotes: 0

ComputerFellow
ComputerFellow

Reputation: 12108

The elif tree is designed such that at anywhere along if one of the statement turns out to be True, the rest of the elifs will not be evaluated.

Here's a tutorial that might help you understand if else better.

Upvotes: 8

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