CODEWITHSUNDEEP
regexvimvim-tabular
rudolph9
rudolph9

Reputation: 8119

Center key and value around hash rocket

Using an vim-tabular I am attempting to format it as follows:

foo = {
    "iSortCol_0" => "1",
    "sSortDir_0" => "desc",
  "iSortingCols" => "1",
   "bSortable_0" => "false",
   "bSortable_1" => "true",
   "bSortable_2" => "false",
   "bSortable_3" => "true",
   "bSortable_4" => "false",
   "bSortable_5" => "true",
   "bSortable_6" => "true",
   "bSortable_7" => "true",
   "bSortable_8" => "true"
}

I have a list of items in a ruby hash formated randomly, eg as follows:

foo = {
      "iSortCol_0" => "1",
"sSortDir_0" => "desc",
    "iSortingCols" =>"1",
     "bSortable_0" =>   "false",
     "bSortable_1" => "true",
     "bSortable_2"=> "false",
     "bSortable_3"  => "true",
     "bSortable_4"   => "false",
     "bSortable_5" => "true",
     "bSortable_6" =>    "true",
     "bSortable_7" =>"true",
     "bSortable_8" => "true"
}

I can get it close using Tab /=> but it does not totally produce the desired result:

foo = {
      "iSortCol_0" => "1",
"sSortDir_0"       => "desc",
    "iSortingCols" => "1",
     "bSortable_0" => "false",
     "bSortable_1" => "true",
     "bSortable_2" => "false",
     "bSortable_3" => "true",
     "bSortable_4" => "false",
     "bSortable_5" => "true",
     "bSortable_6" => "true",
     "bSortable_7" => "true",
     "bSortable_8" => "true"
}

How do I specify how I want let side of the aligned symbol formated? I think I need to utilize \zs or \ze but I'm having difficulty applying them for this purpose.

Upvotes: 0

Views: 137

Answers (1)

Peter Rincker
Peter Rincker

Reputation: 45107

You need to specify the alignment for each section:

Tabularize/=>/r1l1l0

r for right, l for left, and c for center. Each is followed by the number of spaces for each section. So you split on => meaning there is a section before the =>, the => itself, and the portion of text after the =>.

As I am not fond of right aligning you may want to indent your code via =i} then do :Tabularize/=>/.

Upvotes: 1

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