Reputation: 43
I am new in Phonegap. I want to capture photo using Phonegap. I tried the following code from docs but camera is not starting. Please tell me what I made wrong? My code is
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
<script src="js/phonegap.js"></script>
<script src="js/jquery.js"></script>
<script type="text/javascript">
var pictureSource; // picture source
var destinationType; // sets the format of returned value
document.addEventListener("deviceready", onDeviceReady, false);
function onDeviceReady() {
alert("OnDeviceReady...");
pictureSource = navigator.camera.PictureSourceType;
destinationType = navigator.camera.DestinationType;
}
function onPhotoDataSuccess(imageData) {
var smallImage = document.getElementById('smallImage');
smallImage.style.display = 'block';
smallImage.src = "data:image/jpeg;base64," + imageData;
}
function onPhotoURISuccess(imageURI) {
var largeImage = document.getElementById('largeImage');
largeImage.style.display = 'block';
largeImage.src = imageURI;
}
function capturePhoto() {
navigator.camera.getPicture(onPhotoDataSuccess, onFail, {
quality : 50,
destinationType : destinationType.DATA_URL
});
}
function capturePhotoEdit() {
navigator.camera.getPicture(onPhotoDataSuccess, onFail, {
quality : 20,
allowEdit : true,
destinationType : destinationType.DATA_URL
});
}
function getPhoto(source) {
navigator.camera.getPicture(onPhotoURISuccess, onFail, {
quality : 50,
destinationType : destinationType.FILE_URI,
sourceType : source
});
}
function onFail(message) {
alert('Failed because: ' + message);
}
window.onload = onDeviceReady;
</script>
</head>
<body>
<button onclick="capturePhoto();">Capture Photo</button>
<br>
<button onclick="capturePhotoEdit();">Capture Editable Photo</button>
<br>
<button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From
Photo Library</button>
<br>
<button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From
Photo Album</button>
<br>
<img style="display: none; width: 60px; height: 60px;" id="smallImage"
src="" />
<img style="display: none;" id="largeImage" src="" />
</body>
</html>
Please tell me where I made mistake.
this is my camera plugin
<plugins>
<plugin
name="Storage"
value="org.apache.cordova.Storage" />
<plugin
name="Camera"
value="com.foregroundcameraplugin.ForegroundCameraLauncher" />
</plugins>
Thank you in advance.
Upvotes: 0
Views: 3507
Reputation: 159
Try using Phonegap's own camera plugin instead of a custom one.
You can see the documentation here: Phonegap Camera API
Plus, while refering to phonegap.js, you don't have to put js/phonegap.js. You can refer it like src="phonegap.js"
If you are using Phonegap Build, this is the right way to insert your plugin :
<gap:plugin name="org.apache.cordova.camera"/>
Upvotes: 1