CODEWITHSUNDEEP
c#
techtana
techtana

Reputation: 13

How can I run these two methods at the same time C#?

I am trying to get these two pictureboxes to increase in size then decrease in size at the same time using two different methods / while loops. How can I do this? The it works is that when the button is clicked the two picture boxes will increase in size till it reaches a given size then they will both decrease in size.

    private void bthGraph_Click(object sender, EventArgs e)
    {
        red();
        blue();
    }

    private void btnReset_Click(object sender, EventArgs e)
    {
        pbxBlue.Width = 10;
        pbxRed.Width = 10;
    }

    public void red()
    {
        int width = 10;
        while (width < 156)
        {
            width++;
            pbxRed.Width = width;
            pbxRed.Refresh();
            Thread.Sleep(10);
        }
        while (width > 10)
        {
            width--;
            pbxRed.Width = width;
            pbxRed.Refresh();
            Thread.Sleep(10);
        }
    }

    private void blue()
    {
        while (pbxBlue.Width < 156)
        {
            pbxBlue.Width++;
            pbxBlue.Refresh();
            Thread.Sleep(10);
        }
        while (pbxBlue.Width > 10)
        {
            pbxBlue.Width--;
            pbxBlue.Refresh();
            Thread.Sleep(10);
        }
    }
}

Upvotes: 1

Views: 131

Answers (2)

quadroid
quadroid

Reputation: 8940

Every Control can only be updated by the Thread that created it, that said you just cannot access the UI from two threads* simultaneously therefore you just can't achieve what you are trying to do in this way. If you wan't to create an animation why do you need two methods ?

And you should (as already mentioned in the Comments) get rid of the "Thread.Sleep" in the UI Thread, better use a Timer.

*There is a very dirty way to do this by setting the Property CheckForIllegalCrossThreadCalls to false. But this should NEVER be done as it leads to unexpected and untraceable bugs.

Upvotes: 0

Hiral Nayak
Hiral Nayak

Reputation: 1072

try this way 

private void bthGraph_Click(object sender, EventArgs e)
{
    Task[] tasks = new Task[]
    {
       new Task(red),
       new Task(blue),
    };

    foreach(var task in tasks)
       task.Start();

    new Task(red).Start();
    new Task(blue).Start();
}

Upvotes: 2

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