CODEWITHSUNDEEP
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fjardon
fjardon

Reputation: 7996

Where in the standard (C++11) is it said that the remainder operator works for integral type only?

I would like a pointer in the standard (n3242/3291/3290) about where it is defined that the remainder operator doesn't apply to floating point type.

The remainder operator % is defined in 5.6.2

The binary / operator yields the quotient, and the binary % operator yields the remainder from the division of the first expression by the second. If the second operand of / or % is zero the behavior is undefined. For integral operands the / operator yields the algebraic quotient with any fractional part discarded if the quotient a/b is representable in the type of the result, (a/b)*b + a%b is equal to a.

I can't find where it is forbidden to use a floating point type. And the fact the standard explicitly treats integral operands as a special case could be interpreted as: the operator exists for other non-integral types.

I know that MSVC and GCC doesn't accept it, and I looked at lots of answers about this issue, but I can't get a valid pointer in the C++ 11 standard.

Upvotes: 4

Views: 275

Answers (1)

Angew is no longer proud of SO
Angew is no longer proud of SO

Reputation: 171127

C++11, 5.6/2:

The operands of * and / shall have arithmetic or unscoped enumeration type; the operands of % shall have integral or unscoped enumeration type. The usual arithmetic conversions are performed on the operands and determine the type of the result.

(Emphasis mine)

Upvotes: 11

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