CODEWITHSUNDEEP
jqueryangularjsjavascript
Asim Zaidi
Asim Zaidi

Reputation: 28324

javascript function referencing and a parameter passed explaination

I have this code in a code base I am looking at and I am trying to figure out whats going on.

I understand that MyDefinedVariable_1 is getting the instance of some file.js. However I want to know

1- why is MyDefinedVariable_1 referenced at the end of MyDefinedVariable_2 like })(MyDefinedVariable_1). What purpose that serve?

2- What is _super? It seems to me some query thing but not sure

var MyDefinedVariable_1 = require(‘somefile.js);

var MyDefinedVariable_2 = (function (_super) {
..……….
…………    

})(MyDefinedVariable_1);

thanks

Upvotes: 0

Views: 33

Answers (1)

Jacob Mattison
Jacob Mattison

Reputation: 51062

MyDefinedVariable_2 is being set to the results of defining and then calling a function. That function takes a parameter called _super. When the function is being called, MyDefinedVariable_1 is being passed in as the function parameter (so within the function, wherever it says _super the value used will be whatever is assigned to MyDefinedVariable_1).

Here's a simpler example:

var a = 1;
var b = (function(myParam){
  return myParam + 4;
})(a);

After running this, b will be 5. When defining b, we called the function that adds 4 to whatever was passed in (myParam), and what we passed in was a. And a was assigned 1. So b will be 5.

Upvotes: 1

Related Questions