CODEWITHSUNDEEP
phpregexpreg-replace
Martin
Martin

Reputation: 5297

preg_replace pass match through function before replacing

This is what i want to do:

$line = 'blabla translate("test") blabla';
$line = preg_replace("/(.*?)translate\((.*?)\)(.*?)/","$1".translate("$2")."$3",$line);

So the result should be that translate("test") is replaced with the translation of "test".

The problem is that translate("$2") passes the string "$2" to the translate function. So translate() tries to translate "$2" instead of "test".

Is there some way to pass the value of the match to a function before replacing?

Upvotes: 2

Views: 778

Answers (2)

codaddict
codaddict

Reputation: 455010

You can use the preg_replace_callback function as:

$line = 'blabla translate("test") blabla';
$line = preg_replace_callback("/(.*?)translate\((.*?)\)(.*?)/",fun,$line);

function fun($matches) {    
 return $matches[1].translate($matches[2]).$matches[3];    
}

Upvotes: 0

user187291
user187291

Reputation: 53940

preg_replace_callback is your friend

  function translate($m) {
     $x = process $m[1];
     return $x;
  }

  $line = preg_replace_callback("/translate\((.*?)\)/", 'translate', $line);

Upvotes: 6

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